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3 years ago

What is total distance traveled? What is the displacement (change in positions)

Chemistry

1 answer:

erastova [34]3 years ago

8 0

Answer:

Exercise 1

a) 140 m

b) 100 m

c) 180 m

d) 140 m

Exercise 2

a) 20 yards

b) 30 yards

c) 20 yards

d) 55 yards

Exercise 3

a) 11 Kilometers

b) 7 Kilometers

Explanation:

Exercise 1

Distance from B to C = 140 m

Distance from to D = 100 m

Total distance = 100+40+40 = 180 m

Total displacement i.e. distance between A and D is 140 m

Exercise 2

a) Distance from B to C = 35 -15 = 20 yards

b) Distance from C to D = 5 + 35 = 30 yards

c) Distance from B to D = 5 + 15 = 20 yards

d) Displacement = 5 + 50 = 55 yards

Exercise 3

a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers

b) Displacement = 5-2 + 4 = 7 Kilometers

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3 years ago

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$\nu=\frac{c}{\lambda}$

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$\nu=\frac{3\times 10^8m/s}{0.01m}$

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The frequency of photon is, $3\times 10^{10}Hz$

(2) Now we have to calculate the energy of photon.

Formula used :

$E=h\times \nu$

where,

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Now put all the given values in the above formula, we get:

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(3) Now we have to calculate the energy in J/mol.

$E=1.988\times 10^{-23}J/photon$

$E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)$

$E=11.97J/mol$

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

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3 years ago

Read 2 more answers

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Hence, we will calculate the value of K as follows.

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Thus, we can conclude that equilibrium constant for this reaction is $2.8 \times 10^{15}$ .

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2 years ago

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3 years ago

What is total distance traveled? What is the displacement (change in positions) ​

What is total distance traveled? What is the displacement (change in positions)