Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer:
Answer is 24
Step-by-step explanation:

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Answer:
55
Step-by-step explanation:
Factors for 605: 1, 5, 11, 55, 121, and 605
Factors for 55: 1, 5, 11, and 55
So the highest common factor they have is 55.
HCF = 55
60%; Since 1/5 is .2 or 20% and then multiply that by 3.
Answer:
x = -7
Solution:
4(1-x) + 2x = -3( x + 1)
4(1 - x) + 2x = -3 (x + 1)
4(-x + 1) + 2x = -3 (x + 1)
-4x - 4 + 2x = -3(x + 1)
-2x + 4 = -3 (x + 1)