Which is an incorrect rounding for 53.864? 54 53.87 50 53.9

....Help Please......

Bogdan [553]

Answer:

9984000

Step-by-step explanation:

subtract the total by the other number (coverage)

3 0

2 years ago

Read 2 more answers

Please help asap i just need the relationship and measure of x

RSB [31]

Answer:

if it asking for the type of angle the both are obtuse and the fisrt measure is 135 and the second is 101

Step-by-step explanation:

6 0

3 years ago

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When you find the median of a set of data, what quartile would this number be?

IgorC [24]

I think your question isn’t phrased well

7 0

3 years ago

Find the domain and the range of the relation shown in the given graph. Also, determine whether the relation is a function.

Ivahew [28]

Answer:

yes, it is a function

D: {-4, -3, 0, 4}

R: {2, 4}

Step-by-step explanation:

7 0

3 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago