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3 years ago

14

At the start of the 20th century,there were about 100,000 tigers in the wild.In 2014 there were about 3,200.What percent did the

population decrease

1 answer:

Tcecarenko [31]3 years ago

6 0

The population decreased 31.25%

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For a special 16 sided die, what is the theoretical probability for rolling a number less than 9?

Leno4ka [110]

Answer:

8/16

Step-by-step explanation:

there are 16 sides on the dice and there is only 8 number that are less than 9 so that makes it 8/16:)

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A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula

Ilia_Sergeevich [38]

Answer: A. $A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}$

B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

$A=\pi.r^{2}$

So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

$\frac{dA}{dr} =2.\pi.r$

Using $r(t)=3-\frac{363}{(t+11)^{2}}$

$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

Then

$\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]$

$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

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3 years ago

Use cubes. color and draw to show a way to take apart 7.

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What do you mean
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then i could help you

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4 years ago

Tina's favorite shade of teal is made with 7 milliliters of blue paint for every 5 milliliters of green paint. Tyler's favorite

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Answer:

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tyler ratio = 5:7

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3 years ago

Please help me I am on a test

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Answer:

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Step-by-step explanation:

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