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devlian [24]
3 years ago
14

At the start of the 20th century,there were about 100,000 tigers in the wild.In 2014 there were about 3,200.What percent did the

population decrease
Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0
The population decreased 31.25%
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The whole number is 10 the square root is 9
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Jessica wants to buy a purse that costs $25.00. She has already saved
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Answer:

$6

Step-by-step explanation:

19-25

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Write an expression that represents n plus 7 multiplied by 3.
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The <span>expression that represents n plus 7 multiplied by 3 is
(n + 7)(3)
The entire expression, (n + 7) is multiplied by 3 since it would be inconvenient to state the expression as given above if what is meant was
(n + 7x3). It would have simply been n plus 21.</span>
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Algebra 2 Standard Deviation
Illusion [34]

Answer:

don't have answer but have how to do them

Step-by-step explanation:

What are z-scores?

A z-score measures exactly how many standard deviations above or below the mean a data point is.

Here's the formula for calculating a z-score:

z=\dfrac{\text{data point}-\text{mean}}{\text{standard deviation}}z=  

standard deviation

data point−mean

​  

z, equals, start fraction, start text, d, a, t, a, space, p, o, i, n, t, end text, minus, start text, m, e, a, n, end text, divided by, start text, s, t, a, n, d, a, r, d, space, d, e, v, i, a, t, i, o, n, end text, end fraction

Here's the same formula written with symbols:

z=\dfrac{x-\mu}{\sigma}z=  

σ

x−μ

​  

z, equals, start fraction, x, minus, mu, divided by, sigma, end fraction

Here are some important facts about z-scores:

A positive z-score says the data point is above average.

A negative z-score says the data point is below average.

A z-score close to 000 says the data point is close to average.

A data point can be considered unusual if its z-score is above 333 or below -3−3minus, 3. [Really?]

Want to learn more about z-scores? Check out this video.

Example 1

The grades on a history midterm at Almond have a mean of \mu = 85μ=85mu, equals, 85 and a standard deviation of \sigma = 2σ=2sigma, equals, 2.

Michael scored 868686 on the exam.

Find the z-score for Michael's exam grade.

\begin{aligned}z&=\dfrac{\text{his grade}-\text{mean grade}}{\text{standard deviation}}\\ \\ z&=\dfrac{86-85}{2}\\ \\ z&=\dfrac{1}{2}=0.5\end{aligned}  

z

z

z

​  

 

=  

standard deviation

his grade−mean grade

​  

 

=  

2

86−85

​  

 

=  

2

1

​  

=0.5

​  

 

Michael's z-score is 0.50.50, point, 5. His grade was half of a standard deviation above the mean.

Example 2

The grades on a geometry midterm at Almond have a mean of \mu = 82μ=82mu, equals, 82 and a standard deviation of \sigma = 4σ=4sigma, equals, 4.

Michael scored 747474 on the exam.

Find the z-score for Michael's exam grade.

\begin{aligned}z&=\dfrac{\text{his grade}-\text{mean grade}}{\text{standard deviation}}\\ \\ z&=\dfrac{74-82}{4}\\ \\ z&=\dfrac{-8}{4}=-2\end{aligned}  

z

z

z

​  

 

=  

standard deviation

his grade−mean grade

​  

 

=  

4

74−82

​  

 

=  

4

−8

​  

=−2

​  

 

Michael's z-score is -2−2minus, 2. His grade was two standard deviations below the mean.

https://www.khanacademy.org/math/statistics-probability/modeling-distributions-of-data/z-scores/a/z-scores-review

this should help

6 0
3 years ago
Evaluate the function<br> f(x)= 7.45x + 33.7 at x= -4.3
slavikrds [6]
First, you have to substitute for x, which would make the problem f(x)=7.45(-4.3)+33.7
Now, you just have to use the PEMDAS method (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
f(x)= -32.035+33.7
f(x)=1.665
6 0
3 years ago
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