Question

Bob sells tires. He knows that his weekly sales drop if he increases the unit price p (in dollars). The weekly sales are given by an unknown function N(p). His weekly revenue is R(p)=pN(p). Bob is currently selling tires for 100 dollars each. His weekly sales are running at 120 tires per week, so N(100)=120. His marketing department estimates that he will lose 2 sales per week for each 10 dollar increase in unit price, so N′(100)=−0.2. Estimate Bob's increase in weekly revenue for each one dollar increase in tire price.

Answer 1

Answer:

Increase in weakly revenue = $9.8

Explanation:

Price (P) = 100, Demand or Sales N (P) = 120.

So revenue R(P) = P x N(P) = 120 x 100 = 120000

Given : 2 sales per week lost for 10 units increase in price.

New price  (P') = 110 , New Demand or sales N' (P) = 118

So new revenue R' (P) = P' x N' P = 110 x 118 = 12980

Change in Total revenue due to 10 units price rise = 12980 - 120000 = 980

So, change in total revenue due to one unit price rise = 980/ 10 = 9.8