Answer:
Step-by-step explanation:
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Answer:
I think it may be H. but let me know if i am wrong. if i am right plz mark brainliest
Step-by-step explanation:
27 divided by 3 is 9, 27/3=9 because 27/3 is the same exact thing as 27 divided by 3. So the answer has to be 9
We know that m ║ n.
Let's first find the value 'x'.
When two lines are parallel, and a transversal is drawn, the angles on the same side of the transversal are equivalent.
This means that (5x + 16)° and (7x + 4)° are equivalent.
Equating them,
5x + 16 = 7x + 4
16 - 4 = 7x - 5x
12 = 2x
x = 12/2
x = 6°
Since we know the value of 'x', let's substitute them into the angles and find out the actual measurements.
5x + 16 = 5 × 6 + 16 = 30 + 16 = 46°.
7x + 4 = 7 × 6 + 4 = 42 + 4 = 46°.
Now let's find the value of 'y'.
If you observe carefully, (7x + 4)° and (y + 6)° form a linear pair.
This means that both those angles should add upto 180°.
Using that theory, the following equation can be framed:
(y + 6)°+ (7x + 4)° = 180°
Since we know the actual value of (7x + 4)°, let's substitute that value and move ahead.
(y + 6)° + 46° = 180°
y + 6 + 46° = 180
y + 52° = 180°
y = 180° - 52°
y = 128°
Therefore, the values of 'x' and 'y' are 46° and 128° respectively.
Hope it helps. :)
Answer:
(10, - 9 )
Step-by-step explanation:
Given the 2 equations
y = - 2x + 11 → (1)
y = - 3x + 21 → (2)
Substitute y = - 2x + 11 into (2)
- 2x + 11 = - 3x + 21 ( add 3x to both sides )
x + 11 = 21 ( subtract 11 from both sides )
x = 10
Substitute x = 10 into either of the 2 equations and evaluate fir y
Substituting into (1)
y = - 2(10) + 11 = - 20 + 11 = - 9
solution is (10, - 9 )
Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
