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Semenov [28]
3 years ago
7

Jeremy is building a large deck for a community center. The deck is shaped as a rectangle. The width of the deck is 29 feet. The

perimeter of the deck is to be at least 134 feet.
a. Write an inequality that represents all possible values for the length of the deck.

b. Find all possible values for the length of the deck.
Mathematics
1 answer:
sasho [114]3 years ago
6 0
A.
P=2(L+W)
W=29
P is at least (means greater than or equal than ) 134

so
134≤2(L+29) is the inequality


B.
solve
divide both sides by 2
67≤L+29
minus 29 from both sides
38≤L
Length is any value greater than or euqal to 38ft
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A survey of 1100 adults from a certain region​ asked, "If purchasing a used car made certain upgrades or features more​ affordab
Sergio039 [100]

Answer:

a) The p-value of the test is 0.0076 < 0.05, which means that there is evidence of a difference between males and females in the proportion who said they prefer window tinting as a luxury upgrade at the 0.05.

b) The null hypothesis is H_0: \pi_1 - \pi_2 = 0 and the alternate hypothesis is H_1: \pi_1 - \pi_2 \neq 0.

Step-by-step explanation:

Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Females:

49% from a sample of 600. So

\pi_1 = 0.49, s_{\pi_1} = \sqrt{\frac{0.49*0.51}{600}} = 0.0204

Males:

41% from a sample of 500. So

\pi_2 = 0.41, s_{\pi_2} = \sqrt{\frac{0.41*0.59}{500}} = 0.022

Test if there is a difference between males and females in the proportion who said they prefer window tinting as a luxury upgrade.

From here, question b can already be answered.

At the null hypothesis we test if there is no difference, that is, the subtraction of the proportions is 0. So

H_0: \pi_1 - \pi_2 = 0

At the alternate hypothesis, we test if there is a difference, that is, the subtraction of the proportions is different of 0. So

H_1: \pi_1 - \pi_2 \neq 0

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

From the two samples:

X = \pi_1 - \pi_2 = 0.49 - 0.41 = 0.08

s = \sqrt{s_{\pi_1}^2 + s_{\pi_2}^2} = \sqrt{0.0204^2 + 0.022^2} = 0.03

Value of the test statistic:

z = \frac{X - \mu}{s}

z = \frac{0.08 - 0}{0.03}

z = 2.67

Question a:

P-value of the test and decision:

The p-value of the test is the probability that the sample proportion differs from 0 by at least 0.08, which is P(|Z| > 2.670, which is 2 multiplied by the p-value of Z = -2.67.

Looking at the z-table, Z = -2.67 has a p-value of 0.0038.

2*0.0038 = 0.0076

The p-value of the test is 0.0076 < 0.05, which means that there is evidence of a difference between males and females in the proportion who said they prefer window tinting as a luxury upgrade at the 0.05.

6 0
3 years ago
Can someone solve this please
garri49 [273]
I GOT YOU.
First things first,
When multiplying fractions, it's super super super simple. Just multiply the numerator and denominator across, then simplify if needed!
________________________________
To solve your problem,
1. multiply the numerator across.
3 x 4 x 7 = 84
2. multiply the denominator across.
5 x 2 x 3 = 30
3. now you have the fraction \frac{84}{30}  (84/30 if you're on mobile)
4. simplify
84/30 has a common factor of 6. So it simplifies to 14/5.

Your answer is 14/5 
3 0
3 years ago
Evaluate the limit, if it exists. (if an answer does not exist, enter dne.) lim h → 0 (−6 + h)2 − 36 h
Lyrx [107]
The limit can be found by simplifying the expression.
\lim\limits_{h\rightarrow 0}\left(\dfrac{(-6+h)^{2}-36}{h}\right)=\lim\limits_{h\rightarrow 0}\left(\dfrac{-12h+h^{2}}{h}\right)\\\\=\lim\limits_{h\rightarrow 0}(-12+h)\\\\=-12

The limit is -12.

3 0
3 years ago
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What would be the answer in this question?
lianna [129]

use m a t h w a y

Step-by-step explanation:

4 0
3 years ago
Will mark brainlist! Andrea spent $2 to make 10 prints from a photo both. Later, she spent $6 to make 30 prints. Did she get a b
notka56 [123]

Answer:

She got an equally good deal both times

Step-by-step explanation:

\frac{2}{20} can be simplified to make \frac{1}{5}

\frac{6}{30} can be simplified to make \frac{1}{5}

they are the same

3 0
2 years ago
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