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EleoNora [17]
3 years ago
10

The expression like a ton of bricks means very hard would being hit by an actual ton of brick ls hurt If it happened on the moon

?
Physics
1 answer:
Bess [88]3 years ago
7 0

Answer:

If it happened on the moon, the ton of bricks would be hit softly by an actual ton of brick.

Explanation:

Actually, it is about gravity. The brick floats and lands slowly and softly.

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A train travels at 270 km in 3 hours . what is the speed of the train?
Ann [662]

270 \div 3 = 90km / h
3 0
3 years ago
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Poor measurement practices are likely to lead to data that are.....
zhannawk [14.2K]
Inconsistent. You should take three readings at least.
8 0
3 years ago
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The heating element in a kettle behaves like a resistor. A particular kettle needs to operate at 230 V, with a power of 1500 W.
dedylja [7]

Answer:

R = 35.27 Ohms

Explanation:

Given the following data;

Voltage = 230V

Power = 1500W

To find the resistance, R;

Power = V²/R

Where:

V is the voltage measured in volts.

R is the resistance measured in ohms.

Substituting into the equation, we have;

1500 = 230²/R

Cross-multiplying, we have;

1500R = 52900

R = 52900/1500

R = 35.27 Ohms.

Therefore, the resistance which the heating element needs to have​ is 35.27 Ohms.

4 0
3 years ago
A 0.30 kg yo-yo consists of two solid disks of radius 5.10 cm joined together by a massless rod of radius 1.0 cm and a string wr
docker41 [41]

Answer:

0.70046 m/s²

2.732862 N

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of yo-yo = 0.3 kg

R = Radius of rolling disk = 5.1 cm

r = Radius of rod = 1 cm

For a rolling disks the acceleration is given by

a=\frac{g}{1+\frac{R^2}{2r}}\\\Rightarrow a=\frac{9.81}{1+\frac{0.051^2}{2\times 0.01^2}}\\\Rightarrow a=0.70046\ m/s^2

The acceleration of the yo-yo is 0.70046 m/s²

The tension in the string will be

T=m(g-a)\\\Rightarrow T=0.3\times (9.81-0.70046)\\\Rightarrow T=2.732862\ N

The tension in the string is 2.732862 N

8 0
3 years ago
An aircraft is moving horizontally with a speed of 50m/s, at the height of 2km, an object is dropped from the aircraft. What is
posledela

Explanation:

use the diagram^

horizontal velocity of the object nvr changes, it'll stay 50m/s till it hits the ground

initial vertical velocity = 0

to find the final vertical velocity, use the formula:

v {}^{2}  = u {}^{2}  + 2as

where u = 0m/s, a = 9.8m/s², and s = 2000m

solve for v.

for time taken to reach ground, use the formula:

v = u + at

where v = the value for v u calculated above, u = 0 m/s, a = 9.8m/s² and solve for t.

7 0
3 years ago
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