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3 years ago

Please somebody answer I desperately need help!

Physics

2 answers:

padilas [110]3 years ago

8 0

Preserved fossil<span> (like a fossil in amber, ice or tar.</span>

vredina [299]3 years ago

4 0

Amber. The insects would get stuck in the Amber, which is really thick, and it would form around the insect.
I hope this helps.

You might be interested in

If tides occur twice a day in most places. How much time is there between a morning high tide and the next high tide?

algol13

About 12 hours is the time between a morning high tide and the next high tide

Explanation:

The Earth’s rotation happens between two tidal bulges

The “periodic rise and fall” of the surface water levels of the ocean is called tides. The gravitational action and interaction on the earth by the sun and the moon causes these tides. Different regions of the World experiences different patterns of tides like the diurnal, semi-diurnal etc.

When there is one high and one low tide occurring on a lunar day, then it is diurnal pattern. Semi-diurnal pattern occurs when there are two equal high and low tides on a single lunar day.

Since the Earth’s rotation happens between two tidal “bulges” on each lunar day, the coastal areas can experience two high and two low tides in every 24 hours plus 50 minutes.

Accordingly the time between two high tides would be 12 hours plus 25 minutes. Similarly, the time gap between a high to low tide would be 6 hours plus 12.5 minutes.

8 0

2 years ago

The Venus flytrap is known for which of these behaviors?

tensa zangetsu [6.8K]

Snapping a leaf shut around an insect, I think.

8 0

1 year ago

What is the wavelength of a wave with a frequency of 466 Hz and a speed of

Volgvan

Answer:

<h3>The answer is option B</h3>

Explanation:

The wavelength of a wave can be found by using the formula

$\lambda = \frac{c}{f} \\$

where

c is the speed of the wave

f is the frequency

From the question

c = 343 m/s

f = 466 Hz

We have

$\lambda = \frac{343}{466} \\ = 0.73605150...$

We have the final answer as

Hope this helps you

4 0

2 years ago

Two long parallel wires 40 cm apart are carrying currents of 10 A and 20 A in the opposite direction. What is the magnitude of t

Alex_Xolod [135]

Answer:

The magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

Explanation:

Given;

distance half way between the parallel wires, r = ¹/₂ (40 cm) = 20 cm = 0.2 m

current carried in opposite direction, I₁ and I₂ = 10 A and 20 A respectively

The magnitude of the magnetic field halfway between the wires can be calculated as;

$B = \frac{\mu _oI_1}{2 \pi r} + \frac{\mu_oI_2}{2\pi r}$

where;

B is magnitude of the magnetic field halfway between the wires

I₁ is current in the first wire

I₂ is current the second wire

μ₀ is permeability of free space

r is distance half way between the wires

$B = \frac{\mu_o I_1}{2\pi r} + \frac{\mu_o I_2}{2\pi r} \\\\B = \frac{\mu_o }{2\pi r} (I_1 +I_2)\\\\B = \frac{4\pi *10^{-7} }{2\pi *0.2} (10 +20) = 3.0 *10^{-5}\ T$

Therefore, the magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

5 0

2 years ago

A block is released from rest, at a height h, and allowed to slide down an inclined plane. There is friction on the plane. At th

GREYUIT [131]

Here the block has two work done on it

1. Work done by gravity

2. Work done by friction force

So here it start from height "h" and then again raise to height hA after compressing the spring

So work done by the gravity is given as

$W_g = m_A g(h - h_A)$

Now work done by the friction force is to be calculated by finding total path length because friction force is a non conservative force and its work depends on total path

$W_f = -(\mu m_A g cos\theta)(\frac{h}{sin\theta} + \frac{h_A}{sin\theta})$

$W_f = -\mu m_A g cot\theta(h + h_A)$

Total work done on it

$W = m_A g(h - h_A) - \mu m_A g cot\theta(h + h_A)$

So answer will be

None of these

7 0

2 years ago

Read 2 more answers