Let's look at Newton's second law
Force is directly proportional towards mass
If mass is more force will be more.
Between baseball and bowling ball Bowling ball has higher mass
So it would expert most force
Option D
The answer is a newton second law
Answer:
E = 2k ![\frac{\lambda}{ r}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clambda%7D%7B%20r%7D)
Explanation:
Gauss's law states that the electric flux equals the wax charge between the dielectric permeability.
We must define a Gaussian surface that takes advantage of the symmetry of the problem, let's use a cylinder with the faces perpendicular to the line of charge. Therefore the angle between the cylinder side area has the same direction of the electric field which is radial.
Ф = ∫ E . dA = E ∫ dA = q_{int} /ε₀
tells us that the linear charge density is
λ = q_ {int} /l
q_ {int} = l λ
we substitute
E A = l λ /ε₀
is area of cylinder is
A = 2π r l
we substitute
E =
E =
the amount
k = 1 / 4πε₀
E = 2k ![\frac{\lambda}{ r}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clambda%7D%7B%20r%7D)
Answer:
v₂ = 176.24 m/s
Explanation:
given,
angle of projectile = 45°
speed = v₁ = 150 m/s
for second trail
speed = v₂ = ?
angle of projectile = 37°
maximum height attained formula,
![H_{max}= \dfrac{v^2 sin^2(\theta)}{g}](https://tex.z-dn.net/?f=H_%7Bmax%7D%3D%20%5Cdfrac%7Bv%5E2%20sin%5E2%28%5Ctheta%29%7D%7Bg%7D)
now,
![H_{max}= \dfrac{v_1^2 sin^2(\theta_1)}{g}](https://tex.z-dn.net/?f=H_%7Bmax%7D%3D%20%5Cdfrac%7Bv_1%5E2%20sin%5E2%28%5Ctheta_1%29%7D%7Bg%7D)
![H_{max}= \dfrac{v_2^2 sin^2(\theta_2)}{g}](https://tex.z-dn.net/?f=H_%7Bmax%7D%3D%20%5Cdfrac%7Bv_2%5E2%20sin%5E2%28%5Ctheta_2%29%7D%7Bg%7D)
now, equating both the equations
![\dfrac{v_2^2}{v_1^2}=\dfrac{sin^2(\theta_1)}{sin^2(\theta_2)}](https://tex.z-dn.net/?f=%5Cdfrac%7Bv_2%5E2%7D%7Bv_1%5E2%7D%3D%5Cdfrac%7Bsin%5E2%28%5Ctheta_1%29%7D%7Bsin%5E2%28%5Ctheta_2%29%7D)
![\dfrac{v_2^2}{150^2}=\dfrac{sin^2(45^0)}{sin^2(37^0)}](https://tex.z-dn.net/?f=%5Cdfrac%7Bv_2%5E2%7D%7B150%5E2%7D%3D%5Cdfrac%7Bsin%5E2%2845%5E0%29%7D%7Bsin%5E2%2837%5E0%29%7D)
v₂² = 31061.79
v₂ = 176.24 m/s
velocity of projectile would be equal to v₂ = 176.24 m/s
Answer:
The value is ![T_c = 12 .1 ^oC](https://tex.z-dn.net/?f=T_c%20%20%3D%20%2012%20.1%20%5EoC)
Explanation:
From the question we are told that
The mass of the ice cube is ![m_i = 7.50 *10^{-3} \ kg](https://tex.z-dn.net/?f=m_i%20%20%3D%20%207.50%20%2A10%5E%7B-3%7D%20%5C%20%20kg)
The temperature of the ice cube is
The mass of the copper cube is ![m_c = 0.540 \ kg](https://tex.z-dn.net/?f=m_c%20%20%3D%20%200.540%20%5C%20%20kg)
The final temperature of both substance is ![T_f = 0^oC](https://tex.z-dn.net/?f=T_f%20%20%3D%20%200%5EoC)
Generally form the law of thermal energy conservation,
The heat lost by the copper cube = heat gained by the ice cube
Generally the heat lost by the copper cube is mathematically represented as
![Q = m_c * c_c * [T_c - T_f ]](https://tex.z-dn.net/?f=Q%20%3D%20%20m_c%20%20%2A%20%20c_c%20%2A%20%20%5BT_c%20%20-%20%20T_f%20%5D)
The specific heat of copper is ![c_c = 385J/kg \cdot ^oC](https://tex.z-dn.net/?f=c_c%20%20%3D%20385J%2Fkg%20%5Ccdot%20%20%5EoC)
Generally the heat gained by the ice cube is mathematically represented as
![Q_1 = m_i * L](https://tex.z-dn.net/?f=Q_1%20%3D%20%20m_i%20%2A%20L%20)
Here L is the latent heat of fusion of the ice with value ![L = 3.34 * 10^{5} J/kg](https://tex.z-dn.net/?f=L%20%20%3D%20%203.34%20%2A%2010%5E%7B5%7D%20J%2Fkg)
So
![Q_1 = 7.50 *10^{-3} * 3.34 * 10^{5}](https://tex.z-dn.net/?f=Q_1%20%3D%20%207.50%20%2A10%5E%7B-3%7D%20%2A%203.34%20%2A%2010%5E%7B5%7D%20%20%20)
=>
So
=> ![T_c = 12 .1 ^oC](https://tex.z-dn.net/?f=T_c%20%20%3D%20%2012%20.1%20%5EoC)