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goblinko [34]
3 years ago
11

What is 1.2 kg converted into mg. I need to know for step by step please?

Physics
1 answer:
astra-53 [7]3 years ago
4 0
Here’s a good photo to reference when converting in the metric system.

Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.

We are going from 1.2 kg or kilograms, which is at the very top left of the ladder. To get to mg or milligrams, we would have to make six jumps, so we’d move the decimal over six times.

1.2 > 12. > 120. > 1200. > 12000. > 120000. > 1200000.

So our final answer would be 1,200,000mg.
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What is a procedure that could be used to separate a mixture f sugar, black pepper, and pebbles?
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3 years ago
Nerve impulses in a human body travel at a speed of about 100 m/s. Suppose a man accidentally stubs his toe. About how much time
alexandr1967 [171]

Answer:

t = 0.018 s  

Explanation:

given,

nerve impulse in human body travel at a speed of  = 100 m/s

height of the man = 1.80 m

time taken by the impulse to travel from foot to brain = ?

distance = speed × time                      

1.80 = 100 × t                                              

t =\dfrac{1.80}{100}                                    

t = 0.018 s                            

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5 0
3 years ago
How much heat is required to convert 0.3 kilogram of ice at 0°C to water at the same temperature?
Over [174]
<span>The amount of heat required to melt a substance at its melting point is given by
</span>Q=m L_f<span>
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3 0
3 years ago
Read 2 more answers
A bullet with mass 0.04000 kg, traveling at a speed of 310.0 m/s, strikes a stationary block of wood having mass 6.960 kg. The b
ch4aika [34]

Answer:

1.77 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')............................ Equation 1

Where m = mass of the bullet, m' = mass of the block, u = initial velocity of the bullet, u' = initial velocity of the block, V = Velocity of the bullet-wood combination immediately after collision

make V the subject of the equation

V = (mu+m'u')/(m+m').................. Equation 2

Given: m = 0.04 kg, m' = 6.96 kg, u = 310 m/s, u' = 0 m/s (stationary)

Substitute into equation 2

V = (0.04×310+6.96×0)/(0.04+6.96)

V = 12.4/7

V = 1.77 m/s

Hence the speed, in m/s, of the bullet-plus-wood combination immediately after the collision is 1.77 m/s

6 0
3 years ago
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