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kaheart [24]
2 years ago
5

If you are a teenager, then you are younger than 20.

Mathematics
2 answers:
MissTica2 years ago
7 0
A biconditional

brainliest? :)
lana [24]2 years ago
6 0

Answer:

What? I’m 15

Step-by-step explanation:

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Becky wants to fence in a rectangular play area for her dog. If she wants the length of the play area to be 9 feet longer than h
Firdavs [7]

Answer:

The dimension of the play area written algebraically is y²/2 + 9y

Step-by-step explanation:

Let the be x and the width be y

If the length is to be 9 feet longer than half the width,

hence y/2 + 9 = x

hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y

4 0
3 years ago
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What’s the answer to this? Find 1/8 of 88
guapka [62]

Answer:

11

Step-by-step explanation:

\frac{1}{8} of 88

= \frac{88}{8}

= 11

8 0
2 years ago
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Please help ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.
wlad13 [49]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
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Find the derivative.
krek1111 [17]

Answer:

\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding/Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \frac{\sqrt{x}}{e^x}

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Quotient Rule]:                                                                   \displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}
  2. Basic Power Rule:                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}
  3. Exponential Differentiation:                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}
  4. Simplify:                                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}
  5. Rewrite:                                                                                                         \displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}
  6. Factor:                                                                                                           \displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
2 years ago
Gail ran 4610 miles on Saturday and 6810 miles on Sunday. How many miles did Gail run over the weekend?
VMariaS [17]

Answer:

He ran 11,420 miles on the weekend.

Step-by-step explanation:

It's simple: add 4610 and 6810 to get 11,420

hope this helped!

8 0
2 years ago
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