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melisa1 [442]
3 years ago
9

For the values a = 7.2 which is a leg of a right triangle, and value c = 11.1, which is the hypotenuse, find the length of the o

ther leg, b, to the nearest tenth
Mathematics
2 answers:
Margarita [4]3 years ago
7 0
Using pythagora"s theorem you get 

b = sqrt(11,1^2 -7,2^2)

b = sqrt(123,21 -51.84)

b= sqrt71,37

b= 8,448 rounded b= 8,45 but to the nearest tenth b=8,4

hope helped 
KonstantinChe [14]3 years ago
4 0

Answer:The answer is 8.4

Step-by-step explanation:

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No problem just ask me anything and I will be loved to answer anyone question
6 0
3 years ago
Consider in the figure below.
yawa3891 [41]

Here BD is perpendicular bisector

So

  • UB=BV=74

\\ \tt\hookrightarrow UV=74+74=148

Apply Pythagorean theorem

\\ \tt\hookrightarrow BD^2=UD^2-UB^2=UD^2-VD^2

  • UD=VD=78=TD

\\ \tt\hookrightarrow TC^2=TD^2-CD^2

\\ \tt\hookrightarrow TC^2=78^2-30^2

\\ \tt\hookrightarrow TC^2=6084-900=5184

\\ \tt\hookrightarrow TC=72

6 0
2 years ago
Read 2 more answers
Andre earns $12 per hour tutoring students after school. If Andre tutored for 24 hours this month, how much money did he earn th
Sophie [7]

Answer:

$288 dollars

Step-by-step explanation:

12 x 24 = 288

8 0
3 years ago
Read 2 more answers
A factory whistle blows every 30 minutes. The clock tower chimes every 15 minutes. If they both sounded at 1:00 p.M.,at what tim
madam [21]

Answer:

1.30 p.M.

Step-by-step explanation:

The factory whistle blowed at 1:00 p.M, and it blows every 30 minutes, so it will blow again at 1:30 p.M.

The clock tower chimed at 1.00 p.M., and it chimes every 15 minutes, so it will chime again at 1:15 p.M, and after that, it will chime again at 1:30 p.M.

So, you will hear them both at the same time at 1:30 p.M.

We can also solve this problem using LCM:

the least commom multiple between 15 and 30 is 30, so we just need to sum 30 to the inicial time (1:00 p.M.), so the time they will "find each other" again is 1.30 p.M.

7 0
3 years ago
Suppose that, on a 3,000-mile New York to Los Angeles flight, United Continental, American, and Southwest flew a total of 270 em
allsm [11]

Answer:

The number of empty seats each of these three airlines carried on its flight are as follows:

United Continental = 150 empty seats

American = 50 empty seats

Southwest = 70 empty seats

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question. See the attached pdf for the complete question.

The explanation of the answers is now provided as follows:

Let U, A and W represents number of empty seats of United Continental, American, and Southwest respectively. Therefore, we have:

U + A + W = 270 ………………………. (1)

Since United Continental had three times as many empty seats as American, this implies that:

U = 3A ………………………………… (2)

Substituting U = 3A into equation (1), we have:

3A +A + W = 270

4A + W = 270

W = 270 - 4A ………………………….. (3)

For the cost, we have:

3,000[((14.90 / 100) * 3A) + (14.60A / 100) + (12.40W / 100)] = $114,990

((14.90 / 100) * 3A) + (14.60A / 100) + (12.40W / 100) = $114,990 / 3,000

((14.90 / 100) * 3A) + (14.60A / 100) + (12.40W / 100) = 38.33

0.447A + 0.146A + 0124W = 38.33

0.593A + 0.124W = 38.33 ………………… (4)

Substituting W = 270 - 4A from equation (3) into (4) and solve for A, we have:

0.593A + 0.124(270 - 4A) = 38.33

0.593A + 33.48 - 0.496A = 38.33

0.593A - 0.496A = 38.33 - 33.48

0.097A = 4.84

A = 4.84 / 0.097

A = 49.8969072164948

Rounding to a whole number, we have:

A = 50

Substituting A = 50 into each of equations (2) and (3), we have:

U = 3 * 50 = 150

W = 270 - (4 * 50) = 70

Therefore, the number of empty seats each of these three airlines carried on its flight are as follows:

United Continental = 150 empty seats

American = 50 empty seats

Southwest = 70 empty seats

Download pdf
6 0
2 years ago
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