Answer:
reflection from the x-axis
Step-by-step explanation:
given x=2
and the equation

to find the value of q , you need to make q the subject in the equation as shown below
q= 3x-x -4
q=2x-4
but x= 2
so just substitute the value of x in the equation for the q

q=4-4
q=0
therefore the value of q is 0
Raettttttrrrrrrrrrrrrrrrr
Surface area is just the area of all these 4 triangles plus the rectangle.
First we can find the area of the rectangle.

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.


The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

Calculate the area:



We have two of these triangles.

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

Now find the area:



We have two of these triangles.

Add all the areas together:
Move all terms to one sides
3x^2 - 14x - 5 = 0
Split the second term in 3x^2 - 14x - 5 into two terms
3x^2 + x - 15x - 5 = 0
Factor out the common terms in the first two terms, then in the last two terms;
x(3x + 1) - 5(3x + 1) = 0
Factor out the common term 3x + 1
(3x + 1)(x - 5) = 0
Solve for x;
<u>x = -1/3, 5</u>