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fenix001 [56]
3 years ago
12

Fe2O3 + 2A1 - Al2O3 + 2Fe

Chemistry
1 answer:
stepan [7]3 years ago
4 0

I’m assuming in this scenario that 2.5 mols of Fe2O3 is reacting with excess reactant. Based on the balanced equation, you can see that there’s a 1:2 ratio between Fe2O3 and Fe. This means that to find the mols of Fe formed, you need to multiply the mols of Fe2O3 by 2.
2.50mol Fe2O3 * 2mol Fe/1 mol of Fe2O3 = 5.00mols Fe.
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Thermodynamics and Q<br> How much energy is needed to heat 40.5g of water from 15.6°C to 73.0°C
Katyanochek1 [597]

Answer:

9717.246 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of water = 40.5 g

Initial temperature (T₁) = 15.6 °C

Final temperature (T₂) = 73 °C

Specific heat capacity (C) of water = 4.18 J/gºC

Heat (Q) =.?

Next, we shall determine the change in the temperature of water. This can be obtained as follow:

Initial temperature (T₁) = 15.6 °C

Final temperature (T₂) = 73 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 73 – 15.6

ΔT = 57.4 °C

Finally, we shall determine the heat energy required. This can be obtained as follow:

Mass (m) of water = 40.5 g

Specific heat capacity (C) of water = 4.18 J/gºC

Change in temperature (ΔT) = 57.4 °C

Heat (Q) =.?

Q = MCΔT

Q = 40.5 × 4.18 × 57.4

Q = 9717.246 J

Thus, the heat energy required is 9717.246 J

3 0
3 years ago
Why are nails made of iron but not barium and phosphorus?
Marta_Voda [28]

Due to the high strength of iron compared to that of barium and phosphorus the nails are made of iron.

Though iron oxidizes to form rust on reacting with water but it does not explode. Whereas barium reacts vigorously with water with evolution of hydrogen gas. Barium on reacting with other nonmetals results in the formation of poisonous substances. Phosphorus is never found in its pure form in nature and is combustible.

Hence, nails are made up of iron but barium and phosphorus are not suitable for making of nails.

3 0
3 years ago
Read 2 more answers
Help me!!! Several small craters lie in the floor and on the walls of crater 2. Which is older,crater 2 or the smaller craters i
Zinaida [17]
Well, think of it this way. If you put a big paper circle on the ground, and then you put smaller circles on top of the big circle, which one would have been there longer? The big circle, of course. So the same logic applies here: if the smaller craters had been older than the big crater, then when the big crater was formed, the smaller ones would've been buried. Therefore, crater 2 is older than the smaller craters inside it.
Hope that helped! =)
6 0
3 years ago
If 90.0 grams of ethane reacted with excess chlorine,how many grams of dicarbon hexachloride would form
tigry1 [53]

Answer:

709 g  

Step-by-step explanation:

a) Balanced equation

Normally, we would need a balanced chemical equation.

However, we can get by with a partial equation, as log as carbon atoms are balanced.

We know we will need an equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.  

M_r:    30.07          236.74

           C₂H₆ + … ⟶ C₂Cl₆ + …  

m/g:    90.0

(i) Calculate the moles of C₂H₆

n = 90.0 g C₂H₆  × (1 mol C₂H₆ /30.07 g C₂H₆)

  = 2.993 mol C₂H₆

(ii) Calculate the moles of C₂Cl₆

The molar ratio is (1 mol C₂Cl₆/1 mol C₂H₆)

n = 2.993 mol C₂H₆ × (1 mol C₂Cl₆/1 mol C₂H₆)

  = 2.993 mol C₂Cl₆

(iii) Calculate the mass of C₂Cl₆

m = 2.993 mol C₂Cl₆ × (236.74 g C₂Cl₆/1 mol C₂Cl₆)

m = 709 g C₂Cl₆

The reaction produces 709 g C₂Cl₆.

6 0
3 years ago
When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. this result indicates
LuckyWell [14K]
When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. This result of the experiment indicates that most of the volume of a gold atom consists of unoccupied spaces. This was an experiment done by Ernest Rutherford which allowed him to verify the presence of the a small region positive charge in an atom which is called as the nucleus of the atom. Most of the alpha particles pass through the foil while a certain amount were deflected. Those that pass through confirmed that there is a large area that is unoccupied in an atom.
8 0
4 years ago
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