OkSpeed is still the most common factor in fatal road accidents, ... a few kilometres per hour above the speed limit greatly increases the risk of an ... For a car travelling at 70 km/h the risk increased fourfold. ... where Vf is the final velocity, V0 is the initial velocity, a is the rate of deceleration and d is the distance ...
Missing: 240 | Must include: 240
Answer:
1. n = 0.174mol
2. T= 26.8K
3. P = 1.02atm
4. V = 126.88L
Explanation:
1. P= 2.61atm
V = 1.69L
T = 36.1 °C = 36.1 + 273= 309.1K
R = 0.082atm.L/mol /K
n =?
n = PV / RT = (2.61x1.69)/(0.082x309.1)
n = 0.174mol
2. P = 302 kPa = 302000Pa
101325Pa = 1atm
302000Pa = 302000/101325 = 2.98atm
V = 2382 mL = 2.382L
T =?
n = 3.23 mol
R = 0.082atm.L/mol /K
T= PV /nR = (2.98x2.382)/(3.23x0.082) = 26.8K
3. P =?
V = 0.0250 m³ = 25L
T = 288K
n = 1.08mol
R = 0.082atm.L/mol /K
P = nRT/V = (1.08x0.082x288)/25 = 1.02atm
4. P = 782 torr
760Torr = 1 atm
782 torr = 782/760 = 1.03atm
V =?
T = 303K
n = 5.26 mol
R = 0.082atm.L/mol /K
V = nRT/P
V = (5.26x0.082x303)/1.03 = 126.88L
Mass of Calcium phosphate : = 21127.7 g
<h3>Further explanation</h3>
Given
4.1 x 10²⁵ particles of Calcium phosphate
Required
mass
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
mol Calcium phosphate :
n = N : No
n = 4.1 x 10²⁵ : 6.02 x 10²³
n = 68.11
mass Calcium phosphate Ca3(PO4)2 :
= mol x MW
= 68.11 x 310.2 g/mol
= 21127.7 g
= 21.13 kg
Answer:
mass of kI = 74.55 Atomic mass
74.55 g ---> 1 mole
48.9 g --> ?
48.9 / 72
0.7 mole.
In one mole of kI --->
C. 4 decorated cupcakes.
Because 12 divided by 3 = 4, so you can have 4 cupcakes each with 3 cherries