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larisa86 [58]
4 years ago
8

When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. this result indicates

that most of the volume of a gold atom consists of?
Chemistry
1 answer:
LuckyWell [14K]4 years ago
8 0
When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. This result of the experiment indicates that most of the volume of a gold atom consists of unoccupied spaces. This was an experiment done by Ernest Rutherford which allowed him to verify the presence of the a small region positive charge in an atom which is called as the nucleus of the atom. Most of the alpha particles pass through the foil while a certain amount were deflected. Those that pass through confirmed that there is a large area that is unoccupied in an atom.
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Two liquids of different temperatures are separated by a barrier. The hot liquid is on the right side and the cold one is on the
nasty-shy [4]

Answer:

b

Explanation:

7 0
3 years ago
Please help I need it
lubasha [3.4K]

Answer : The structure are shown below and the number of stereoisomers are possible in 3,5-dimethylnonane and 3,7-dimethyle-5-ethyldecane are 4 and 8 respectively.

Explanation :

Chiral carbon : It is carbon which is attached to the different types of atoms or molecules.

The number of stereoisomers possible for a compound is related to the number of chiral centers (n) present in it as,

\text{Number of stereoisomers}=2^n

where,

'n' is the number of chiral carbon present in the compound.

The number of chiral carbon present in 3,5-dimethylnonane is, 2 that means n = 2 (carbon-3 and carbon-5)

\text{Number of stereoisomers}=2^n=2^2=4

The number of stereoisomers are possible in 3,5-dimethylnonane is, 4

The number of chiral carbon present in 3,7-dimethyle-5-ethyldecane is, 3 that means n = 3 (carbon-3, carbon-5 and carbon-7)

\text{Number of stereoisomers}=2^n=2^3=8

The number of stereoisomers are possible in 3,7-dimethyle-5-ethyldecane is, 8

4 0
3 years ago
One crystalline form of silica (SiO2) has a cubic unit cell, and from X-ray diffraction data it is known that the cell edge leng
Sav [38]

Answer:

8 Silicon atom are present in unit cell.

16 oxygen atoms are present unit cell.

Explanation:

Number of atoms in unit cell = Z =?

Density of silica = tex]2.32 g/cm^3[/tex]

Edge length of cubic unit cell = a  = 0.700 nm = 0.700\times 10^{-7} cm

1 nm=10^{-7} cm

Molar mass of Silica  = 28.09 g/mol+16.00\times 2=60.09 g/mol

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

2.32 g/cm3=\frac{Z\times 60.09 g/mol}{6.022\times 10^{23} mol^{-1}\times (0.700\times 10^{-7}cm)^{3}}

Z = 8

1 silicon is 2 oxygen atoms. then 8 silicon atoms will be 16 oxygen atoms.

5 0
4 years ago
BRAINLIEST IF ANSWERED CORRECTLY WITH EXPLANATION! HELP PLEASE:)
elena-14-01-66 [18.8K]

First question

Pb(NO_3)_2 + KI \rightarrow PbI_2 + KNO_3

Balaneced:

Pb(NO_3)_2 + 2KI \rightarrow PbI_2 + 2KNO_3

Find how many moles potassium iodide it is in 345.0 grams

n_{KI} = \frac{345.0 \ g}{166.0 \ g/mol} = 2.078 \ mole

Find how many moles potassium nitrate there is for 2.078 moles KI

n_{KNO_3} = \frac{2}{2} \cdot n_{KI} = 2.078 \ mole

Find how many grams potassium nitrate there is in 2.078 moles KNO_3

m_{KNO_3} = 2.078 \ mol \cdot 101.1 \ g/mol = 210.1 \ g

Second question

yield \ \% = \frac{experimental}{theoretical} \cdot 100 = \frac{195.3 \ grams}{210.1 \ grams} \cdot 100 = 93.0 \ \%

4 0
3 years ago
What us the definition of half-life?
UNO [17]
Half-life is the time required for the amount of something to fall to half its initial value. This term is usually used in nuclear physics to describe how quickly unstable atoms undergo decay, or how long stable atoms survive, radioactive decay, and it is also used more generally of any type of exponential or non-exponential decay.

In simpler terms: this is when an isotopes radioactivity is cut in half
7 0
3 years ago
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