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loris [4]
4 years ago
8

A person drove at a speed of 28 miles per hour on a back road during a recent trip. They can drive the same distance at 44 mph o

n the interstate in three hours less. What is the distance they drove on the back road?
Mathematics
1 answer:
Mila [183]4 years ago
4 0

Answer:

the answer is 15

Step-by-step explanation:

i know this right.

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3 feet of ribbons are needed for wrapping each present. How many presents can be wrapped with 102cm of ribbons?
bagirrra123 [75]

1 imperial foot has approximately 30.48 metric centimeters, and for one present we need 3 ft, or namely 3(30.48) cm, how many can we get from 102 cm?   102 ÷ 3(30.48) ≈ 1.1155, so barely just one present.

8 0
3 years ago
Read 2 more answers
Evaluate P(3, 3) <br> 1<br> 9<br> 6
solong [7]
Hence, the value of P(3,3) is 6
5 0
3 years ago
Chissy had 4 gallons of gas in her tank when she arrived at the gas station. She pumped gas into her car at a rate of 3/10 gallo
igomit [66]

Answer:

4 + (3s/10) gallons

Step-by-step explanation:

Originally, there are 4 gallons. Add that to the expression. Every second, 3/10 gallon are filled. So s times 3/10 equal the total number of gallons added. Add both expressions together to get the answer.

5 0
3 years ago
What measures of variation indicate spread about the mean?
KIM [24]
<span>standard deviation and variance</span>
7 0
4 years ago
Read 2 more answers
The number of tourists at the beach per weekend in July was 55,000, In November, the number of tourists per weekend was 18,000.
Ganezh [65]

Answer:

The percentage change from July to November is 67.27 %

Step-by-step explanation:

Given as :

The number of tourists at the beach per weekend in the month of July = x_1 = 55,000

The number of tourists at the beach per weekend in the month of November = x_2 = 18,000

Let the percentage change from July to November = A %

Or,  % decrease change = \dfrac{\tetxtrm new value - \textrm old value}{\textrm old value} × 100

So , A % = \dfrac{\tetxtrm [tex]x_2   - \textrm  x_1 }{\textrm  x_1 }[/tex] × 100

or, A % = \frac{55000 - 18000}{55000} × 100

Or, A % = \frac{37000}{55000} × 100

Or, A  = 67.27 %

So percentage change between two months = 67.27 %

Hence The percentage change from July to November is 67.27 % Answer

6 0
4 years ago
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