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Svet_ta [14]
3 years ago
12

How long did it take for Troy’s toy truck to accelerate at 1.2 m/s² from 0.40 to 0.80 meters per second? A. 33 s B. 0.33 s C. 3.

0 s D. 3.0 min
Mathematics
1 answer:
givi [52]3 years ago
5 0

Answer:

i dont knnow

Step-by-step explanation:

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How many boards he can paint
katrin2010 [14]
Idk but just divide both of the fraction hope i helped you a little
4 0
3 years ago
Consider the equality xy k. Write the following inverse proportion: y is inversely proportional to x. When y = 12, x=5.​
skelet666 [1.2K]

Answer:

y=\dfrac {60} {x}   or   xy=60   (depending on your teacher's format preference)

Step-by-step explanation:

<h3><u>Proportionality background</u></h3>

Proportionality is sometimes called "variation".   (ex. " 'y' varies inversely as 'x' ")

There are two main types of proportionality/variation:

  1. Direct
  2. Inverse.

Every proportionality, regardless of whether it is direct or inverse, will have a constant of proportionality (I'm going to call it "k").

Below are several different examples of both types of proportionality, and how they might be stated in words:

  • y=kx      y is directly proportional to x
  • y=kx^2     y is directly proportional to x squared
  • y=kx^3     y is directly proportional to x cubed
  • y=k\sqrt{x}}   y is directly proportional to the square root of x
  • y=\dfrac {k} {x}   y is inversely proportional to x
  • y=\dfrac {k} {x^2}   y is inversely proportional to x squared

From these examples, we see that two things:

  • things that are <u>directly proportional</u> -- the thing is <u>multipli</u>ed to the constant of proportionality "k"
  • things that are <u>inversely proportional</u> -- the thing is <u>divide</u>d from the constant of proportionality "k".

<h3><u>Looking at our question</u></h3>

In our question, y is inversely proportional to x, so the equation we're looking at is the following y=\dfrac {k} {x}.

It isn't yet clear what the constant of proportionality "k" is for this situation, but we are given enough information to solve for it:  "When y=12, x=5."

We can substitute this known relationship pair, and find the "k" that relates this pair of numbers:

<h3><u>Solving for k, and finding the general equation</u></h3>

General Inverse variation equation...

y=\dfrac {k} {x}

Substituting known values...

(12)=\dfrac {k} {(5)}

Multiplying both sides by 5...

(12)*5= \left ( \dfrac {k} {5} \right ) *5

Simplifying/arithmetic...

60=k

So, for our situation, k=60.  So the inverse proportionality relationship equation for this situation is y=\dfrac {60} {x}.

The way your question is phrased, they may prefer the form: xy=60

7 0
2 years ago
What is the equation of the line through (−2, −2) and (4, −5)?
Liono4ka [1.6K]

Answer:

y = -1/2x - 3

Step-by-step explanation:

slope: (y2-y1) / (x2-x1)

(-5 - -2) / (4 - -2)

(-5 + 2) / (4 + 2)

-3 / 6

- 1 / 2

y-intercept: y = mx + b

-5 = -1/2(4) + b

-5 = -2 + b

-3 = b

7 0
2 years ago
Equivalent ratios for 8:28​
Tpy6a [65]

Answer:

8                :                 28

x2                                   x2

          16:56

Step-by-step explanation:

4 0
3 years ago
Help me with this please!!
valina [46]
<h2><u>Given:</u><u>-</u></h2>

  • Points C = (-7,2) → \sf{(X_1,Y_1)}
  • D = (3,12) → \sf{(X_2,Y_2)}

<h2><u>To </u><u>Find</u><u>:</u><u>-</u></h2>

  • The Midpoint of CD.

<h2><u>Required</u><u> </u><u>Response</u><u>:</u><u>-</u></h2>

Let,

Midpoint of CD be (x,y).

WKT,

\boxed{\sf{(x,y) = \frac{X_1+X_2}{2},\frac{Y_1+Y_2}{2}}}

→\;{\sf{\frac{-7+3}{2},\frac{2+12}{2}}}

→\;{\sf{\frac{-4}{2},\frac{14}{2}}}

→\;{\sf{-2,7}}

The Midpoint of CD ◕➜ \Large{\red{\mathfrak{(-2,7)}}}

Let,

The centre be O

Radius = CO & OD

Here, C = (-7,2) → \sf{(X_1,Y_1)}

O = (-2,7) → \sf{(X_2,Y_2)}

\boxed{\sf{Distance = \sqrt{(X_2-X_1)²+(Y_2-Y_1)²}}}

→\;{\sf{\sqrt{(-2+7)²+(7-2)²}}}

→\;{\sf{\sqrt{5²+5²}}}

→\;{\sf{\sqrt{25+25}}}

→\;{\sf{\sqrt{50}}}

→\;{\sf{5√2 (or) 7.07}}

Radius of Circle ◕➜ \Large{\red{\mathfrak{7.07}}}

<h2>Option D.</h2>

Hope It Helps You ✌️

3 0
3 years ago
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