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2 years ago

Plz help me solve this page ASAP 20POINTS!!!!!

Mathematics

1 answer:

eduard2 years ago

8 0

1) Midpoint : (7/2,1/2), Quadrant 1

2. Midpoint: (5,1/2), Quadrant 2

Hope this helps. Please mark brainliest if you can

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The HCF of 36 72 63<br>The LCM of 8 9 12

MakcuM [25]

LCM of 8,9,12 is 72

HCF of 36 72 63 is 3

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2 years ago

How do you write this in standard form? (6-7i)/(1-2i)

xenn [34]

$\frac { \left( 6-7i \right) }{ \left( 1-2i \right) } \cdot 1\\ \\ =\frac { \left( 6-7i \right) }{ \left( 1-2i \right) } \cdot \frac { \left( 1+2i \right) }{ \left( 1+2i \right) } \\ \\ =\frac { 6+12i-7i-14{ i }^{ 2 } }{ 1+2i-2i-4{ i }^{ 2 } }$

$\\ \\ =\frac { 6+5i-14\left( -1 \right) }{ 1-4\left( -1 \right) } \\ \\ =\frac { 6+5i+14 }{ 1+4 } \\ \\ =\frac { 20+5i }{ 5 } \\ \\ =\frac { 20 }{ 5 } +\frac { 5i }{ 5 } \\ \\ =4+i$

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3 years ago

Determine the axis of symmetry of the Quadratic equation.

Marat540 [252]

B/X=2
OWA OWA 20 minimum word

7 0

2 years ago

Read 2 more answers

What is 4.3(v+2.5)=8.11+4v

True [87]

Answer:

-8.8

Step-by-step explanation:

We begin by simplifying the parenthesis through multiplication. Parenthesis is a structure which signals multiplication happening.

$4.3(v+2.5)=8.11+4v\\4.3v+10.75=8.11+4v$

We now begin combining like terms across the equal sign by performing the inverse or doing the opposite. Move first the 8.11 by subtracting it from both sides.

$4.3v+10.75-8.11=8.11-8.11+4v\\4.3v+2.64=4v$

Now, move 4.3v across by subtracting it from both sides.

$4.3v-4.3v+2.64=4v-4.3v$

$2.64=-0.3v$

Finally, we divide both sides by the coefficient of v.

$\frac{2.64}{-0.3} =\frac{-0.3v}{-0.3} \\-8.8=v$

6 0

3 years ago

You buy 1.75 pounds of apples and 2.05 pounds of oranges. Apples and oranges sell for the same price per pound. The total cost,

dlinn [17]

Answer:

$1.75c+2.05c=4.18\\\\Per\ pound\ cost=c=\$1.1$

Step-by-step explanation:

$Cost\ of\ per\ pound\ apple=Cost\ of\ per\ pound\ oranger=c\\\\$

Cost of Apples:

$Amount\ of\ apples=1.75\ pounds\\\\Cost\ of\ apples=Amount\times per\ pound\ cost\\\\Cost\ of\ apples=1.75\times c\\\\Cost\ of\ apples=1.75c$

Cost of oranges:

$Amount\ of\ oranges=2.05\ pounds\\\\Cost\ of\ oranges=Amount\times per\ pound\ cost\\\\Cost\ of\ oranges=2.05\times c\\\\Cost\ of\ oranges=2.05c$

Total cost:

$Total\ cost\ of\ fruits=cost\ of\ apple+cost\ of\ oranges\\\\Total\ cost\ of\ fruits=1.75c+2.05c\\\\After\ coupon\ cost=\$ 3.43\\\\ Original\ cost=After\ coupon\ cost+coupon\ amount\\\\ Original\ cost=3.43+0.75=4.18$

$1.75c+2.05c=4.18\\\\3.8c=4.18\\\\c=\frac{4.18}{3.8}\\\\c=1.1\\\\Per\ pound\ cost\ of\ fruits=\$1.1$

4 0

3 years ago