Answer:
it would be a
Step-by-step explanation:
Minus 16x both sides and add 28 to both sides
x^2-16x+28=0
factor
hmm, what 2 numbers multiply to 28 and add to -16
hmm
1 and 28? nope
2 and 14? yep
since middle term is negative and last tem is positive, both of the factors are negative
(x-14)(x-2)=0
set each to zero
x-14=0
x=14
x-2=0
x=2
x=2 and 14
Answer:2
Step-by-step explanation:
Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
