Question

Solve by using Pythagorean Theorem, a= 5, b= x-1, and c=x

Answer 1

The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

Step-by-step explanation:

The given is,

             a = 5

             b = x - 1

             c = x

Step:1

      Pythagorean theorem is,

              $a^{2} + b^{2} = c^{2}$................................(1)

      (  It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides )

      From the given values the equation (1) becomes,

                       $5^{2} + (x-1) ^{2} = x^{2}$

                             ( $(a-b)^{2} = a^{2} + b^{2} -2ab$ )

               25 + ( $x^{2}$ + 1 - 2x ) = $x^{2}$

                           25 + 1 -2x = 0               ( ∵ Eliminate $x^{2}$ in both sides)

                                     26 = 2x

                                       x = 13

Step:2

        From the values of x,

                   a = 5

                    b = ( 13 - 1 ) = 12

                   c = 13

Result:

            The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.