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Nikolay [14]
3 years ago
6

Any mathematics genius around. To solve this question.. am giving the brainliest

Mathematics
1 answer:
Likurg_2 [28]3 years ago
7 0
Well
It is in the form of a/b + b/a = (a sqr + b sqr)ab

Substitute
(Sin sqr theta + cos sqr theta) +2 cos theta + 1. 2 + 2cos theta
———————————————————————— = ————————-
Sin theta(1+cos theta). Sin theta (1 + cos theta)

2(1+ cos theta)/sin theta(1 + cos theta). {1 + cos theta cancelled}
2/sin theta. Hope it helps :}
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Would the scale factor 4/5 reduce, enlarge, or preserve?
Ivan

The first one would reduce the size because it would now be 4/5 of the actual size

The scale factor 7/2 would enlarge it because it is getting 3 1/2 time larger than the oringanl size

5 0
3 years ago
Read 2 more answers
In ΔPQR, sin R = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D" id="TexFormula1" title="\frac{3}{5}" alt="\frac{3}{5}"
solong [7]

Answer:

Since we know that ΔPQR is a right triangle, we can also asume that:

sin R = cos P = 3/5

So the answer is (d).

* This formular can also be applied to other right triangles.

In a right triangle, sine of one acute angle will always be equal to cosine of the other acute angle.

And we can check this by actually finding cos P using the lengths of the sides, by calculating PR first:

PR = √(PQ² + RQ²) = √(12² + 16²) = 20

=> cos P = PQ/PR = 12/20 = 3/5

6 0
3 years ago
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taurus [48]

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The linear relationship between the length of someone's femur and their expected height..

4 0
2 years ago
Can you help me with destributive property
Semmy [17]
So it’s like

ab + ac = a(b + c)

7 0
4 years ago
Find the least common multiple for each list of numbers 5, 7
ddd [48]
Multiples of 5 are: 5,10,15,20,25,30,35,40,45,.......

Multiples of 7 are: 7,14,21,28,35,42,49,63,......


So the least common number is these two sets is 35, which is <span>the least common multiple</span> of 5 and 7


Hope you got it
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