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trapecia [35]
3 years ago
7

rectangle with the dimension: width (6b-2)in and length (4a+3)in. if a=.75 and b=.50, what is the perimeter of the rectangle?

Mathematics
1 answer:
Greeley [361]3 years ago
6 0
4(.75) + 3
3 + 3
6
-------------------
6(.50) - 2
3 - 2
1

P = 2 (l + w)
P = 2(6 + 1)
P = 2 x 7
P = 14
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Suppose r(140°, P)(A) = B and (RPD←→∘RPC←→)(A) = B, what is m∠CPD?
NISA [10]

An angle bisector divides an angle into two equal halves.

The measure of angle \angle CPD is 70 degrees

The complete question is an illustrates the concept of angle bisector;

Where:

\angle RPD = 140^o, and line PC bisects \angle RPD

Because line PC bisects \angle RPD, then it means that the measure of RPD is twice the measure of CPD:

So, we have:

\angle RDP = 2 \times \angle CPD

Substitute \angle RPD = 140^o

140^o = 2 \times \angle CPD

Divide both sides by 2

70^o = \angle CPD

Apply symmetric property of equality:

\angle CPD = 70^o

Hence, the measure of angle \angle CPD is 70 degrees

Read more about angle bisectors at:

brainly.com/question/12896755

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Find the factors from the roots, then multiply the factors together.
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2 years ago
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Answer:

Step-by-step explanation:

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Answer: 54

-------------------------------------------------------------------

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Or you can use a proportion to get
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