rectangle with the dimension: width (6b-2)in and length (4a+3)in. if a=.75 and b=.50, what is the perimeter of the rectangle?
1 answer:
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Answer:
a =
x =
Step-by-step explanation:
Let's solve for a.
8x−5x+4−x=ax+8
Step 1: Flip the equation.
ax+8=2x+4
Step 2: Add -8 to both sides.
ax+8+−8=2x+4+−8
ax=2x−4
Step 3: Divide both sides by x.
Let's solve for x.
8x−5x+4−x=ax+8
Step 1: Add -ax to both sides.
2x+4+−ax=ax+8+−ax
−ax+2x+4=8
Step 2: Add -4 to both sides.
−ax+2x+4+−4=8+−4
−ax+2x=4
Step 3: Factor out variable x.
x(−a+2)=4
Step 4: Divide both sides by -a+2.
Hope this helps!
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