Answer:
12:3:1
Explanation:
<em>The typical F2 ratio in cases of dominant epistasis is 12:3:1.</em>
<u>The epistasis is a form of gene interaction in which an allele in one locus interacts with and modifies the effects of alleles in another locus</u>. There are different types of epistasis depending on the type of alleles that are interacting. These include:
- Dominant/simple epistasis: Here, a dominant allele on one locus suppresses the expression of both alleles on another locus irrespective of whether they are dominant or recessive. Instead of the Mendelian dihybrid F2 ratio of 9:3:3:1, what is obtained is 12:3:1. Examples of this type of gene interaction are found in seed coat color in barley, skin color in mice, etc.
- Other types of epistasis include <em>recessive epistasis (9:3:4), dominant inhibitory epistasis (13:3), duplicate recessive epistasis (9:7), duplicate dominant epistasis (15:1), and polymeric gene interaction (9:6:1).</em>
The genotype of the plant is <span>WwXxYyZz.
The plant has a 50% chance of passing each of the alleles of a gene, the dominant or the recessive.
So, for producing the haploid genotype of a gamete </span><span>Wxyz the chance is
0,5 (W)* 0,5 (x)* 0,5 (y) * 0,5( z)= 0,0625
</span><span>
</span>
Answer:
Option C
Explanation:
Option
A. 6440 mL/min
B. 4340 mL
C. 3500 mL/min
D. 2940 mL/min
Solution
It is required to find the minute ventilation which is equal to the product of rate of breathing and the total amount of gas being inhaled or exhaled per breathe. Let this minute ventilation be denoted by "
"
Thus,

where TD is the tidal volume and Br is the rate of breathing
Substituting the given values we get

We will now reduce the air held in the conducting zone of respiratory system
Air held per breathe 
Total Air held

Amount of fresh air one can breathe in and out every minute

Hence, Option C is correct
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I know this answer but it is really commutated