You are measuring the mass, weight, and density.
Answer:
The correct answer is ''post-zygotic barrier to reproduction''
Explanation:
Biological barriers prevent the exchange of genes between two or more populations, a postzygotic reproductive barrier reduces the survival or reproduction of hybrid offspring. In hybrid non-viability there is low survival of the hybrid, especially during embryonic stages. On the other hand, the sterility of the hybrid occurs when the fertilized egg develops into a healthy but sterile adult. Segregation of aneuploid gametes during meiosis, different gene associations occur on the chromosomes of the parents.
Answer:
AUNQUE el porcentaje de oxígeno en el aire inspirado es constante a diferentes altitudes, la caída de la presión atmosférica a mayor altitud disminuye la presión parcial del oxígeno inspirado y, por lo tanto, la presión impulsora del intercambio de gases en los pulmones.
Explanation:
Answer:
94.1 L
Explanation:
The number of liters produced when 126g of glucose is completely reacted with O2 is calculated as follows
find the moles of C6H12O6 used that is moles = mass /molar mass
= 126g /180 g/mol = 0.7 moles
from the equation
C6H12O6 +6O2 = 6CO2 +6 H2O
the reacting ratio of C6H12O6 to Co2 is 1:6 therefore the moles of CO2 = 0.7 x6/1= 4.2 moles
At STP 1 moles of a gas = 22.4 L
what about 4.2 L = how many liters
cross multipication
= (4.2moles x 22 .4 L)/ 1mole = 94.1 L