My Question:
Is there any answer choices?
SOLUTION
From the given data the mean is 62 and standard deviation is 4
It is required to find the probability that a data value is between 57 and 62
That is:
The z scores is calculated using:
Using the x values it follows:
Also,
Thus the required probability is:
![P(-1.25The proability is:[tex]P(-1.25This can be expressed as percentage as:[tex]P(-1.25\lt z\lt0.75)=66.8\%](https://tex.z-dn.net/?f=P%28-1.25The%20proability%20is%3A%5Btex%5DP%28-1.25This%20can%20be%20expressed%20as%20percentage%20as%3A%5Btex%5DP%28-1.25%5Clt%20z%5Clt0.75%29%3D66.8%5C%25)
Therefore the correct option is C
The correct answer is y= 0.513(1.833)^x
Explain
We will use the equation on this form
Y=ab^x
Let’s us plug in the coordinates of first point
(X, y) , ( 9, 120)
We will have
Y=ab^x
120= ab^9
Our equation for a will be
Ab^9 = 120
ab ^9 / b^9 = 120/ b^9
a = 120/ b^9
So will have
Y= 120/ b^9 • b^x
Then we will plug in coordinates for the second point
( x,y) = ( 10, 220)
We will have
Y= 120/b^9 • b^x
220 = 120/b^9 • b^10-9
220= 120b
Divide both side by 120
B= 11/6
B= 1.833333 = 1.833
Let’s plug in the value b=11/6 to our equation for a
A= 120/b^9
A= 120/ 11/6^9
A= 120/11^9/6^9
A=120 • 6^9 / 11^9
= 0.51285 which equal to 0.513
So therefore the answer is
Y= 0.513(1.833)^x
I hope this help you
:D
Answer:
The answer is C.
Step-by-step explanation:
I just did the test and the answer was C
