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dexar [7]
3 years ago
7

PLS Help im sooo stuck on this question pls help and show your work and please dont put a nonsense answer

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0

XY = xZ

85b + 83 = 91b - 283

Subtract 85b from both sides:

83 = 6b - 283

Add 283 to both sides:

6b = 366

Divide both sides by 6:

B = 61

Now replace b with 61 and solve for the length:

85(61) + 83

5185 + 83 = 5268

The length is 5,268

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Solve s=πr^2+πrl for l
NemiM [27]

Start with

S = \pi r^2 + \pi r l

Subtract \pi r^2 from both sides:

S - \pi r^2=\pi r l

Divide both sides by \pi r

\dfrac{S-\pi r^2}{\pi r}=l

And thus we solved the expression for l:

l=\dfrac{S-\pi r^2}{\pi r}

5 0
3 years ago
Please help me with this question, and show the work . Thank you so much !!!!
jenyasd209 [6]
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6 0
4 years ago
Can you help with this?
g100num [7]

Answer:

c or d

Step-by-step explanation:

good luck

hope this helps

need more answer? just follow me

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8 0
3 years ago
In a genetics experiment on peas, one sample of offspring contained green peas and yellow peas. Based on those results, estimate
dem82 [27]

Complete Question

In a genetic experiment on peas, one sample of offspring contained 436 green peas and 171 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected? The probability of getting a green pea is approximately: Is the probability reasonably close to 3/4?

Answer:

The  probability is  P(g) =0.72

Yes the result is reasonably close

Step-by-step explanation:

From the question we are told that

   The  number of  of  green peas is  g =  436

     The number of yellow peas is  y  = 171

   The sample size is  n  =  171 +  436 =  607

The probability of getting an offspring pea that is green is mathematically represented as

       P(g) = \frac{g}{n}

        P(g) = \frac{436}{607}

        P(g) =0.72

Comparing  P(g) =0.72  to   \frac{3}{4}  =  0.75 we see that the result is reasonably close

7 0
4 years ago
Pleas help this is due today!!
harkovskaia [24]
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3 years ago
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