Answer:
33.33% probability that it takes Isabella more than 11 minutes to wait for the bus
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X lower than x is given by the following formula.
For this problem, we have that:
Uniformly distributed between 3 minutes and 15 minutes:
So 
What is the probability that it takes Isabella more than 11 minutes to wait for the bus?
Either she has to wait 11 or less minutes for the bus, or she has to wait more than 11 minutes. The sum of these probabilities is 1. So
We want P(X > 11). So
33.33% probability that it takes Isabella more than 11 minutes to wait for the bus
4 times 4=16 So in four days, Cheyrl traveled 16 miles.
Answer:
12x³ - 3x
Step-by-step explanation:
<em>Given </em>
<em>f(</em><em>x</em><em>)</em><em> </em><em>=</em><em> </em><em>x </em><em>and </em><em>g(</em><em>x</em><em>)</em><em> </em><em>=</em><em> </em><em>4x²</em><em> </em><em>-</em><em> </em><em>1</em>
<em>Now</em><em>, </em>
<em>3</em><em> </em><em>f(</em><em>x</em><em>)</em><em> </em><em>*</em><em> </em><em>g(</em><em>x</em><em>)</em><em> </em>
<em>=</em><em> </em><em>3</em><em> </em><em>*</em><em> </em><em>x </em><em>(</em><em>4x²</em><em> </em><em>-</em><em> </em><em>1</em><em>)</em>
<em>=</em><em> </em><em>3x </em><em>(</em><em> </em><em>4x²</em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>)</em>
<em>=</em><em> </em><em>12x³</em><em> </em><em>-</em><em> </em><em>3x </em>
<em>Hope </em><em>it </em><em>will </em><em>help </em><em>:</em><em>)</em>
Consider this option:
1. if the point (4;6) is the centre of the circle and the point (2;5) is the first endpoint of its diameter, then point (4;6) is the middle point of the diameter (it means that is the middle between the 1st and the 2d endpoints of diameter).
2. using the property described above:
for x of the 2d endpoint of the diameter: x=4*2-2=6;
for y of the 2d endpoint of the diameter: y=6*2-5=7.
answer: (6;7)
C=2pr, r=c/(2p)
a=pr^2, using r found above we get:
a=p(c^2/(4p^2))
a=(c^2)/(4p), since c=106.76 and we approximate pi as 3.14
a=(106.76^2)/(4*3.14)
a=11612.2176/12.56 cm^2
a≈924.54 cm^2 (to nearest one-hundredth of a square cm)
