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Romashka [77]
3 years ago
6

What is the length of the third side of a right triangle if it is known that the two of the sides have lengths 5 and 13. How man

y solutions does this problem have?
Mathematics
2 answers:
Vikki [24]3 years ago
6 0

Answer:

2 solutions: 12 or \sqrt{194}

Step-by-step explanation:

5 cannot be the hypotenuse as it is shorter than 13, which means that the length of the third side is either \sqrt{13^{2} - 5^{2} } (12) or \sqrt{5^{2}+13^{2}  } (\sqrt{194}).

bulgar [2K]3 years ago
6 0

The answer is 12

So yeah

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(4x+8)+(2x+20)=90 help me solve this and draw a diagram
Lemur [1.5K]

Answer:

x = 31/3

Step-by-step explanation:

4x+8+2x+20=90

4x+2x+8+20=90

4x+2x+8+20=90

6x+28=90

6x+28-28=90-28

6x=62

x = 31/3

5 0
3 years ago
2y+8x=1 in slope intercept form
anzhelika [568]
The slope-intercept form is y = mx + b.
Following that kind of form becomes
2y = -8x + 1
y =(-8x + 1)/2
y = -4x + 1/2

Hope this helps <span>✌️</span>☺️✌️
6 0
4 years ago
Can you help me pls lol I’m doing a test
Schach [20]

Answer:

Dont say your doing a test, brainly is strict and will delete your question because its timed

Step-by-step explanation:

6 0
3 years ago
Solve the problem<br> -4p - 4p
Minchanka [31]

\bold{Hey\  there!}

\bold{-4p - 4p = \ ?}\\\ \bold{-4 - 4 = -8}\\\bold{-p - p = -p}\\\bold{-4p - 4p=\underline{-8p}}\\\boxed{\boxed{\bold{Answer: -8p}}}\checkmark

\text{\bold{Good luck on your assignment and enjoy your day!}}

~\frak{LoveYourselfFirst:)}

6 0
3 years ago
Read 2 more answers
HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r
lesya692 [45]

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression 2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\

Then we find the LCM of the resulting function

= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\=  \frac{7x}{10} + 2\frac{1}{2}y+6\\

The final expression gives the required answer

7 0
3 years ago
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