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Romashka [77]
3 years ago
6

What is the length of the third side of a right triangle if it is known that the two of the sides have lengths 5 and 13. How man

y solutions does this problem have?
Mathematics
2 answers:
Vikki [24]3 years ago
6 0

Answer:

2 solutions: 12 or \sqrt{194}

Step-by-step explanation:

5 cannot be the hypotenuse as it is shorter than 13, which means that the length of the third side is either \sqrt{13^{2} - 5^{2} } (12) or \sqrt{5^{2}+13^{2}  } (\sqrt{194}).

bulgar [2K]3 years ago
6 0

The answer is 12

So yeah

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Will give brainliest
V125BC [204]

Answer:

B

Step-by-step explanation:

Basically, this question is asking the legs of the triangle shown in the graph.

In this right triangle, there are 2 legs and one of them is 6400 meters. We were asked to find out the length of the other led. And we know the angle is 16.5 deg.

Using Tangent  to find out:

set the length of the other leg is x meters.

tan(16.5) = 6400/x

x= 6400/tan(16.5)

x= 21606 m

7 0
2 years ago
Read 2 more answers
Can someone help pls.
kap26 [50]

<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>

<em>I think, to start out, we could set up the problem like so</em>

<em>15 + t ≥ 26</em>

<em>because t is not a set number. </em>

<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>

<em>t ≥ 11</em>

<em>So the resulting answer is t ≥ 11.</em>

<em />

<em>I hope that my interpretation helps.</em>

<em>-Toremi</em>

<em />

8 0
3 years ago
Read 2 more answers
The A&amp;M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a
Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0
3 years ago
40% of what number is 82?
Naya [18.7K]
82*100/40 = 205 

<span>40% 0f 205 = 205*40% = 205*40/100 = 82
hopes this helps :) :D :)</span>
4 0
3 years ago
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Caroline’s cell phone plan costs $32 per month. Which table shows the sum of the amounts that Caroline will pay for her cell pho
Greeley [361]

Answer:

the answer is j

Step-by-step explanation:

32 plus 32 is 64 and 32 plus 64 is 96 so foth and so on

5 0
3 years ago
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