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pshichka [43]
4 years ago
15

Use the Distributive Property to write equivalent expressions for each of the following

Mathematics
2 answers:
sergij07 [2.7K]4 years ago
6 0
(5x6) + (5x) (hope this helps!)
aleksklad [387]4 years ago
5 0
(5•6)+(5x)
Answer- 30+5x
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Which of the following arcs are congruent in the circle below?
BartSMP [9]

Answer:

C

Step-by-step explanation:

CB is congruent to AB because the both are 30 degrees

8 0
3 years ago
A class of 40 students elected a class president. There were 12 votes for Candidate A, and 18 votes for Candidate B.
Helen [10]
Hey there, Bulgogi!

The correct answer will be the first one since [I'm assuming] you know that to calculate the percentage of something, it's the amount of that something divided by the total amount but since only 30 students voted [12+18] multiplied by 100.

So, we are calculating the percentage on votes and 12 students voted for Candidate A so our Numerator will be 12 and our Denominator will be the total amount of student who voted, so 30 [or 12+18]

Once put into a fraction, we will get \frac{12}{12+18} which would be equals to 2/5 or 0.4. Now we multiply by 100 and we get a total of 40% for Candidate A.

Thank you for using Brainly.
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4 0
4 years ago
Kate has 10 stickers. One half of them are purple. How many of Kate’s stickers are purple?
stiks02 [169]

Answer:

5

Step-by-step explanation:

Half of ten is five  so Kate’s has five purple stickers

8 0
3 years ago
What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n
Yakvenalex [24]

Answer:

(\sqrt{2},-1),(-\sqrt{2},-1)

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

-2x^{2} +y=-5 ----> equation A

y=-3x^{2} +5 -----> equation B

solve by substitution

substitute equation B in equation A

-2x^{2} +(-3x^{2} +5)=-5

solve for x

-5x^{2} +5=-5

-5x^{2}=-10

x^{2}=2

x=\pm\sqrt{2}

<em>Find the value of y</em>

y=-3x^{2} +5

For x=\sqrt{2} ----> y=-3(\sqrt{2})^{2} +5=-1

For x=-\sqrt{2} ----> y=-3(-\sqrt{2})^{2} +5=-1

therefore

The solutions are

(\sqrt{2},-1),(-\sqrt{2},-1)

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

8 0
4 years ago
Read 2 more answers
Solve this system of equations: y=(3/4)x; y=-x-7 *
ladessa [460]

Answer: x

=

−

4

,

y

=

−

11

Step-by-step explanation:

6 0
3 years ago
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