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3 years ago

Which two parameters can both be measured in meters

Physics

2 answers:

MatroZZZ [7]3 years ago

5 0

The Correct answer is A

Lera25 [3.4K]3 years ago

3 0

I believe the answer is A.

Explanation:

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How much do the plates move annually?

Phantasy [73]

Answer:

UP TO four inches but usually a little slower than that

Explanation:

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3 years ago

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1200 meters is less than 1 kilometer

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<span>1200 meters is less than 1 kilometer
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4 years ago

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A constant electric field of magnitude E = 148 V/m points in the positive x-direction. How much work (in J) does it take to move

DochEvi [55]

Answer:

$W=-2.1405\times 10^9\,J$

Explanation:

Given:

electric field, $E=148\,V.m^{-1}$

charge, $Q=-13\,\mu C=-13\times 10^{-6}\,C$

initial position coordinates, $p1 =(-18,-131)$

final position coordinates, $p2 =(107,76)$

We find the distance through which the charge has been moved:

$d=\sqrt{(x1-x2)^2+(y1-y2)^2}$

Where we have (x1,y1) & (x2,y2) as the initial and final coordinates of the points.

$d=\sqrt{(107-(-81))^2+(76-(-131))^2}$

$d= 279.63\,m$

Now we need the angle through which displacement is made with respect to the direction of electric field.

$tan\,\theta= \frac{y2-y1}{x2-x1}$

$\theta= tan^{-1}[\frac{76-(-131)}{107-(-81)} ]$

$\theta= 47.75^{\circ}$

Now from the relation between the change in potential difference:

$\Delta V= E.d.cos\,\theta$

$\Delta V= 148\times 279.63\times cos\,47.75^{\circ}$

$\Delta V= 27826.06 V$

∵The change in voltage is defined as the work done per unit charge.

∴ $\Delta V=\frac{W}{Q}$

$W=\frac{\Delta V}{Q}$

Putting the respective values

$W=\frac{27826.06 }{-13\times 10^{-6}}$

$W=-2.1405\times 10^9\,J$

3 0

3 years ago

If three balls of different materials were dropped at the same time from the same height, which would hit the ground first? (Ass

8_murik_8 [283]

Answer:

It depends of the mass and weight of each of the materials

Explanation:

8 0

3 years ago

You want to photograph a circular diffraction pattern whose central maximum has a diameter of 1.0 cm . You have a helium-neon la

Nataly [62]

Answer:

71 cm

Explanation:

The formula to apply here is θ = 1.22λ/D,

diameter of central maximum =1.0 cm

wavelength, λ= 633 nm

Diameter of pinhole = 0.11 mm

where θ = arc length/distance = s/R

s/R = 1.22λ/D

(.005)/R = (1.22)(633 X 10^-9)/(1.1 X 10^-4)

R = .71 m which is 71 cm

6 0

3 years ago