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3 years ago

Is this right? if not how do u do it?

Physics

1 answer:

Ronch [10]3 years ago

3 0

You've definitely got the right idea and your procedure is correct.

But I see one mistake for sure, plus a few other things that
I'm not sure of.

The mistake for sure: If the ending water is 12 ml,
then the beginning water is 9 ml, not 11 ml.

Things I'm not sure of:

-- I'm not sure that I'm remembering correctly at the moment,
but I have a sneaking hunch that you're supposed to read the
level at the BOTTOM of the meniscus, not the top.
It won't matter, because the DIFFERENCE will be the same
either way. But if the teacher wants you to read from the bottom,
then your numbers may be marked wrong.

-- The question at the bottom asks for the "volume of cherry",
but I seem to see TWO cherries in the water. Does than mean
they expect you to take only half of the displacement ?

-- They ask for "volume of cherry" twice.
Maybe that means they want you to end up with the volume in cm³
instead of ml. (The number is the same.)

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Convert the following to relative uncertainties <br>a) 2.70 ± 0.05cm<br>b) 12.02 ± 0.08cm

DENIUS [597]

data which is expressed in form of following way

$a = a_o + \Delta a$

here in above expression

$a_o$ = true value

$\Delta a$ = uncertainty in the value

now the relative uncertainty is given as

$\frac{\Delta a}{a_o}$

now by above formula we can say

a) 2.70 ± 0.05cm

here

True value = 2.70

uncertainty = 0.05

Relative uncertainty = $\frac{0.05}{2.70}$ = 0.0185

b) 12.02 ± 0.08cm

here

True value = 12.02

uncertainty = 0.08

Relative uncertainty = $\frac{0.08}{12.02}$ = 0.00665

4 0

3 years ago

Beers of snakes thunderstorms darkness in water are classified as blank phobias

Scrat [10]

I believe all of these would be known as specific phobias.

4 0

3 years ago

The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (o

LUCKY_DIMON [66]

Answer:

The average impact force is 12000 newtons.

Explanation:

By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:

$\bar F \cdot \Delta t = m \cdot (v_{2}-v_{1})$ (1)

Where:

$\bar F$ - Average impact force, in newtons.

$\Delta t$ - Duration of the impact, in seconds.

$m$ - Mass of the sledge hammer, in kilograms.

$v_{1}$ , $v_{2}$ - Initial and final velocity, in meters per second.

If we know that $\Delta t = 0.0020\,s$ , $m = 4\,kg$ , $v_{1} = -6\,\frac{m}{s}$ and $v_{2} = 0\,\frac{m}{s}$ , then we estimate the average impact force is: