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goldenfox [79]
3 years ago
5

A baseball is batted. It's a long fly ball. 4 seconds later the ball reaches the outfield 100 meters away and returns to the hei

ght from which it left the bat. Determine the horizontal component of the ball's initial velocity in magnitude, in m/s,
Physics
1 answer:
Vitek1552 [10]3 years ago
8 0

Answer:

25 m/s

Explanation:

First we should define the variables

T=4

Dx = 100

ay=-9.8

ax=0

We can use formula 1 from the BIG 5

x=(v+v0)t/2

By plugging in our variables we can get 100=4(v+v0)/2

Which is 50=v+v0

v=v0 since horizontal acceleration always equals zero

so 2v0 = 50

v0 = 25

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Answer:

B

Explanation:

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Electrons have a negative charge of -1,

Neutrons have a neutral charge of about 0.

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3 years ago
Rainwater draining from a neighborhood street initially travels at 4 ft/s through a pipe with a cross-sectional area of 15.7 ft2
Fudgin [204]

Answer:

The  velocity  is v_2  =  0.96 \ ft/s

Explanation:

From the question we are told that

   The initial speed is  v_1  =  4 \ ft/s

   The  cross -sectional area of the first pipe is  A_1  =  15.7 \ ft

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Generally from continuity equation we have that

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So  

     v_2  =  \frac{A_1 *  v_1  }{A_2 }

=>   v_2  =  \frac{15.7  *  4  }{65.4 }

=>   v_2  =  0.96 \ ft/s

6 0
3 years ago
How did settlers changed the great plains?
Paul [167]
They farmed it and got rid of most of the buffalo. They also caused the locust plague from turning up the eggs in the dirt when it was first plowed.
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3 years ago
A length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be
ycow [4]
The equivalent resistance of resistors connected in parallel is
\frac{1}{R_{eq}} = \frac{1}{R_1} +  \frac{1}{R_2} + ...
In our problem, we have 5 identical resistor of resistance R, so their equivalent resistance is
\frac{1}{R_{eq}} =  5 (\frac{1}{R} )
The problem also says that the equivalent resistance is R_{eq}= 17 \Omega, so we can find the resistance R of each piece of wire:
R=5 R_{eq} = 5 \cdot 17 \Omega = 85 \Omega

In the initial wire, it's like the 5 pieces are connected in series, so the equivalent resistance of the wire is just the sum of the resistances of the 5 pieces:
R_{wire} = 5 R = 5 \cdot 85 \Omega = 425 \Omega
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3 years ago
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Explanation:

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hope it helps!

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