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ss7ja [257]
2 years ago
8

The two types of grip in table tennis are 1. ___________ and 2. _____________.

Physics
1 answer:
pshichka [43]2 years ago
8 0
  1. The two types of grip in table tennis are <u>penhold grip</u> and <u>shakehand grip</u>.
  2. A <u>serve</u> is a stroke that starts a rally.
  3. A <u>receive</u> is a stroke to reply to a <u>serve</u>.
  4. A let is a <u>rally</u> of which the result is <u>not scored</u>.
  5. A point is a rally of which the result is scored.

<h3>What is table tennis?</h3>

Table tennis can be defined as an indoor sport and recreational activity in which two (2) or four (4) players hit a ping-pong ball back and forth on a table that is divided into halves by a low net, especially through the use of a small-solid bat (racket).

<h3>Types of grip in table tennis.</h3>

Generally, there are two (2) main types of grip in table tennis and these include:

  • Shakehand grip
  • Penhold grip

<h3>The fundamental skills of table tennis.</h3>

Basically, there are four (4) fundamental skills used in table tennis and these are:

  1. Forehand drive
  2. Backhand drive
  3. Backhand push
  4. Forehand push.

Read more on table tennis here: brainly.com/question/17358010

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Under which condition does Ohm's law apply? a. The current must be constant b. The power must be constant c. The temperature mus
ruslelena [56]

Answer:

option c

Explanation:

The temperature must be constant. Ohms law states that the current running through a conductor is directly proportional to the potential difference across it provided the temperature remains constant

6 0
2 years ago
A mass of 5 kg of saturated water vapor at 150 kPa is heated at constant pressure until the temperature reaches 200°C. Calculate
yulyashka [42]

Answer:

The work done by the steam is 213 kJ.

Explanation:

Given that,

Mass = 5 kg

Pressure = 150 kPa

Temperature = 200°C

We need to calculate the specific volume

Using formula of work done

W=Pm\DeltaV

W=Pm(\dfrac{RT_{1}}{P_{atm}}-\dfrac{RT_{2}}{P_{atm}}

W=\dfrac{PmR}{P_{atm}}(T_{2}-T_{1})

Where,R = gas constant

T = temperature

P = pressure

P_{atm}=Atmosphere pressure

m = mass

Put the value into the formula

W=\dfrac{150\times10^{3}\times5\times287.05}{1.01\times10^{5}}\times(473-373)

W=213\ kJ

Hence, The work done by the steam is 213 kJ.    

6 0
3 years ago
a 1 gram spiders sits on a platform rotating at 78 rpm. the spider is 15 cm from the centre disk. find the speed of the spider
olga nikolaevna [1]

The spider is traveling in a circle with radius = 15cm

The circumference of any circle = <em>2 pi (radius)</em>
The circumference of the spider's path = 2 pi (15 cm) = 30 pi cm

The spider completes a trip around this path 78 times per minute.
Its speed, relative to you, is   

                               (78) x (30 pi) cm/min =

                                       2,340 pi cm/min =  7,351.33 cm/min =

                                     <em>  73.5133 meter/min =</em>

                                       <em>4.411 km/hr =</em>

                                         <em>2.74  miles/hour

</em>
(After the last appearance of pi,
all numbers are rounded.)<em>

</em>
8 0
3 years ago
A cat leaps into the air to catch a bird with an initial speed of 2.74 m/s at an angle of 60.0° above the ground. What is the hi
Volgvan

Answer: D. 0.29 m

Explanation:

We will use the following equations to describe the leap of the cat:

y=V_{o}sin\theta t-\frac{gt^{2}}{2}   (1)

V_{y}=V_{oy}-gt   (2)

Where:

y  is the height of the cat  

V_{oy}=V_{o}sin\theta is the cat's initial velocity

\theta=60\°

g=9.8m/s^{2}  is the acceleration due gravity

t is the time

V_{y} is the y-component of the velocity

Now the cat will have its maximum height y_{max} when V_{y}=0. So equation (2) is rewritten as:

0=V_{oy}-gt   (3)

Finding t:

t=\frac{V_{oy}}{g}=\frac{V_{o}sin\theta}{g}   (4)

t=\frac{2.74 m/s sin(60\°)}{9.8m/s^{2}}   (5)

t=0.24 s   (6)

Substituting (6) in (1):

y_{max}=(2.74 m/s)sin(60\°) (0.24 s)-\frac{(9.8m/s^{2})(0.24 s)^{2}}{2}   (7)

Finally:

y_{max}=0.287 m \approx 0.29 m   (8)

3 0
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How was newton's laws used to solve problems on apollo 13 ship<br> Explain in two full paragraphs
MaRussiya [10]

Answer:

actually ships are made in newtons third law of motion.it states to every action there is equal and opposite reaction. curved is made in downwards to maintain upthrust and to made balance.

actually it prevents ships from drowning and to move with a heavy mass.

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