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ss7ja [257]
2 years ago
8

The two types of grip in table tennis are 1. ___________ and 2. _____________.

Physics
1 answer:
pshichka [43]2 years ago
8 0
  1. The two types of grip in table tennis are <u>penhold grip</u> and <u>shakehand grip</u>.
  2. A <u>serve</u> is a stroke that starts a rally.
  3. A <u>receive</u> is a stroke to reply to a <u>serve</u>.
  4. A let is a <u>rally</u> of which the result is <u>not scored</u>.
  5. A point is a rally of which the result is scored.

<h3>What is table tennis?</h3>

Table tennis can be defined as an indoor sport and recreational activity in which two (2) or four (4) players hit a ping-pong ball back and forth on a table that is divided into halves by a low net, especially through the use of a small-solid bat (racket).

<h3>Types of grip in table tennis.</h3>

Generally, there are two (2) main types of grip in table tennis and these include:

  • Shakehand grip
  • Penhold grip

<h3>The fundamental skills of table tennis.</h3>

Basically, there are four (4) fundamental skills used in table tennis and these are:

  1. Forehand drive
  2. Backhand drive
  3. Backhand push
  4. Forehand push.

Read more on table tennis here: brainly.com/question/17358010

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pochemuha

Answer:

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Explanation:

this is to help people not play games lolllll

6 0
3 years ago
What is the focal length of the eye-lens system when viewing an object at infinity? Assume that the lens-retina distance is 2.0
Wittaler [7]

Answer:

Focal length of the eye-lens is 2.0 cm

Explanation:

Given:

An eye-lens system which will follow converging lens (convex lens) sign conventions and knowing that lens-retina distance is the image distance.

Object distance, u = -\infty

Image distance, v = 2.0 cm

We have to find the focal length.

Lets say that the focal length is f .

Lens Formula:

⇒ \frac{1}{f} =\frac{1}{-u} +\frac{1}{v}

Sign-convention:

We will follow the Cartesian coordinate,placing the lens at the origin of the plane, optical center is at (0,0) now as the object will be towards negative x-axis so it is negative others are on the right side of the origin so they are positive.

Using the lens formula:

⇒ \frac{1}{f} =\frac{1}{-u} +\frac{1}{v}

⇒ \frac{1}{f} =\frac{1}{-\infty} +\frac{1}{2.0}      

⇒ \frac{1}{f} =0+\frac{1}{2.0}         <em>...as </em> \frac{1}{\infty}=0 a<em>nd there is no </em>-0<em> so it is zero only.</em>

⇒ f=2.0 cm

So the focal length is 2.0 cm with two significant figures.

7 0
3 years ago
A 1.8-m uniform rod is being used to balance two buckets of paint. One pucket is full, but the other is mostly empty, and has on
Lisa [10]

Answer: 0.36 m

Explanation:

By definition, the x coordinate of the center of mass of the system obeys the following equation:

Xm = (m1x1 + m2x2 + …….+ mnxn) / m1+m2 +……+ mn

Neglecting the mass of the rod, and choosing our origin to be coincident with the location of the full bucket, we can write the following expression for the X coordinate of the center of mass (Assuming that both masses are aligned over the x-axis, so y-coordinates are zero):

Xm = 0.25 mb . 1.8 m / (1+0.25) mb

Simplifying mb, we get:

Xm= 0.36 m (to the right of the full bucket).

6 0
3 years ago
This grandfather clock, made entirely of Legos, has a 0.625 m long simple pendulum. What is the period of the pendulum? (include
PSYCHO15rus [73]

1. 1.59 s

The period of a pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}}

where L is the length of the pendulum and g the gravitational acceleration.

In this problem,

L = 0.625 m

g = 9.81 m/s^2

Substituting into the equation, we find

T=2\pi \sqrt{\frac{(0.625 m)}{9.81 m/s^2}}=1.59 s

2. 54,340 oscillations

The total number of seconds in a day is given by:

t=24 h \cdot 60 min/h \cdot 60 s/min =86,400 s

So in order to find the number of oscillations of the pendulum in one day, we just need to divide the total number of seconds per day by the period of one oscillation:

N=\frac{t}{T}=\frac{86,400 s}{1.59 s}=54,340

3. 0.842 m

We want to increase the period of the pendulum by 16%, so the new period must be

T'=T+0.16T=1.16 T = 1.16 (1.59 s)=1.84 s

Now we can re-arrange the equation for the period of the pendulum, using T=1.84 s, to find the new length of the pendulum that is required to produce this value of the period:

L=g(\frac{T}{2\pi})^2=(9.81 m/s^2)(\frac{1.84 s}{2\pi})^2=0.842 m

6 0
3 years ago
What is the purpose of the commutator in an electric motor?
Alex777 [14]
<span>Commutator is the moving part of the electric motor and periodically reverses the current direction between the rotor and the external circuit.One end of the coil is attached to each half of the commutator.  Commutator are used so when electricity flows through the circuit, the coil will rotate continually in the same direction.</span>



8 0
3 years ago
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