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2 years ago

The two types of grip in table tennis are 1. _ and 2. ___.

Physics

1 answer:

pshichka [43]2 years ago

8 0

The two types of grip in table tennis are penhold grip and shakehand grip.
A serve is a stroke that starts a rally.
A receive is a stroke to reply to a serve.
A let is a rally of which the result is not scored.
A point is a rally of which the result is scored.

<h3>What is table tennis?</h3>

Table tennis can be defined as an indoor sport and recreational activity in which two (2) or four (4) players hit a ping-pong ball back and forth on a table that is divided into halves by a low net, especially through the use of a small-solid bat (racket).

<h3>Types of grip in table tennis.</h3>

Generally, there are two (2) main types of grip in table tennis and these include:

Shakehand grip

Penhold grip

<h3>The fundamental skills of table tennis.</h3>

Basically, there are four (4) fundamental skills used in table tennis and these are:

Forehand drive
Backhand drive
Backhand push
Forehand push.

Read more on table tennis here: brainly.com/question/17358010

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shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const

Contact [7]

Answer:

a) $T=0.40 N$

b) $T=1.9 s$

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

$P=2\pi r=0.94$

$r=\frac{0.94}{2\pi}=0.15 m$

Now, we need to find the angle of the pendulum from vertical.

$tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17$

$\alpha=9.44 ^{\circ}$

Let's apply Newton's second law to find the tension.

$\sum F=ma_{c}=m\omega^{2}r$

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

$Tcos(\alpha)=mg$ (1)

The horizontal equation of motion will be:

$Tsin(\alpha)=m\omega^{2}r$ (2)

a) We can find T usinf the equation (1):

$T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N$

We can find the angular velocity (ω) from the equation (2):

$\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s$

b) We know that the period is T=2π/ω, therefore:

$T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s$

I hope it helps you!

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2 years ago

A car is moving from rest and the velocity increases to 30 m/s in 4 seconds. Calculate its acceleration.

vaieri [72.5K]

Answer:

7.5 m/s²

Explanation:

Given:

v₀ = 0 m/s

v = 30 m/s

t = 4 s

Find: a

v = at + v₀

(30 m/s) = a (4 s) + (0 m/s)

a = 7.5 m/s²

8 0

3 years ago

I will fan and give 2 medals!!!!!!

Maksim231197 [3]

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IV. rises above chromospheres

V. anchored to surface (sun’s surface)

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I. Intense High-energy

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V. Emits radiation

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I. Surface dark spots

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III. Solar magnetic storms

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I did this in class I got 100%

7 0

3 years ago

A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic

miss Akunina [59]

Answer:

0.07756 m

Explanation:

Given mass of object =0.20 kg

spring constant = 120 n/m

maximum speed = 1.9 m/sec

We have to find the amplitude of the motion

We know that maximum speed of the object when it is in harmonic motion is given by $v_{max}=A\omega$ where A is amplitude and $\omega$ is angular velocity