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Dmitry_Shevchenko [17]
3 years ago
6

to what height will a 250g soccer ball rise to if it is kicked directly upwards at 8 meters per second​

Physics
2 answers:
Nonamiya [84]3 years ago
6 0

Answer:

3.2 m

Explanation:

we know

Hmax = V²/2g

= 8² / 2*10 = 3.2

Mashcka [7]3 years ago
5 0

Answer:

The ball will get upto the height of 3.26 meters.

Explanation:

Initial velocity of the ball = u = 8 m/s

final velocity of the ball = v = 0 m/s ( upward)

Acceleration due to gravity ,a= -g =-9.8 m/s^2

Height of the ball when kicked = s

Using third equation of motion :

v^2-u^2=2as

(0 m/s)^2-(8 m/s)^2=2\times (-g)\times s

(0 m/s)^2-(8 m/s)^2=2\times (-9.8)\times s

s=\frac{(-8 m/s)^2}{2\times -9.8 m/s^2}=3.26 m

The ball will get upto the height of 3.26 meters.

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A 0.20-kg block rests on a frictionless level surface and is attached to a horizontally aligned spring with a spring constant of
solmaris [256]

Answer:

0.57 ms^{-1}

Explanation:

k = spring constant of the spring = 40 Nm⁻¹

A = amplitude of the simple harmonic motion = 4 cm = 0.04 m

m = mass of the block attached to spring = 0.20 kg

w = angular frequency of the simple harmonic motion

Angular frequency of the simple harmonic motion is given as w = \sqrt{\frac{k}{m} } \\w = \sqrt{\frac{40}{0.20} }\\w = 14.14 rads^{-1}

v = Speed of the block as it pass the equilibrium point

Speed of the block as it pass the equilibrium point is given as

v = A w\\v = (0.04) (14.14)\\v = 0.57 ms^{-1}

6 0
3 years ago
An observer is approaching at stationary source at 17.0 m/s. Assuming the speed of sound is 343 m/s, what is the frequency heard
UNO [17]

Answer:

the frequency heard by the observer is equal to 2677 Hz

Explanation:

given,      

velocity of the observer = 17 m/s

speed of the sound = 343 m/s    

velocity of the source = 0 m/s    

frequency emitted from the source  = 2550 Hz              

f = f_0(\dfrac{v-v_0}{v-v_s})              

f = 2550\times (\dfrac{343+17}{343-0})

velocity of observer is negative as it is approaching the source.                   f = 2676.38 Hz ≈ 2677 Hz                    

hence, the frequency heard by the observer is equal to 2677 Hz

7 0
3 years ago
Which part of the planet had the highest concentration of ozone in 1989?
Nat2105 [25]

Answer:

earth

sorry I need points but I don’t know the answer again I’m really sorry

4 0
2 years ago
A capacitor with plates separated by a distance d is charged to a potential difference ΔVC. All wires and batteries are disconne
Tom [10]

Answer:

Explanation:

Initial separation of plate = d

final separation = 2d

The capacitance of the capacitor will reduce from C to C/2 because

capacitance = ε A / d

d is distance between plates.

As the batteries are disconnected , charge on the capacitor becomes fixed .

Initial charge on the capacitor

= Capacitance x potential difference

Q = C ΔV

Final charge will remain unchanged

Final charge = C ΔV

Final capacitance = C/2

Final potential difference = charge / capacitance

= C ΔV /  C/2

= 2 ΔV

Potential difference is doubled after the pates are further separated.

6 0
3 years ago
A rectangular plate, whose streamwise dimension (or chord c) is 0.2 m and whose width (or span b) is 1.8 m, is mounted in a wind
34kurt

Answer:

Answer  for the question is given in the attachment.

Explanation:

Download pdf
4 0
3 years ago
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