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Dmitry_Shevchenko [17]

3 years ago

6

to what height will a 250g soccer ball rise to if it is kicked directly upwards at 8 meters per second

2 answers:

Nonamiya [84]3 years ago

6 0

Answer:

3.2 m

Explanation:

we know

Hmax = V²/2g

= 8² / 2*10 = 3.2

Mashcka [7]3 years ago

5 0

Answer:

The ball will get upto the height of 3.26 meters.

Explanation:

Initial velocity of the ball = u = 8 m/s

final velocity of the ball = v = 0 m/s ( upward)

Acceleration due to gravity ,a= -g = $-9.8 m/s^2$

Height of the ball when kicked = s

Using third equation of motion :

$v^2-u^2=2as$

$(0 m/s)^2-(8 m/s)^2=2\times (-g)\times s$

$(0 m/s)^2-(8 m/s)^2=2\times (-9.8)\times s$

$s=\frac{(-8 m/s)^2}{2\times -9.8 m/s^2}=3.26 m$

The ball will get upto the height of 3.26 meters.

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Answer:

The net force acting on the object is doubled while the mass of the object is held constant. What will be the new acceleration? An object has an acceleration of 12.0 m/s^2. The net force acting on the object is halved (decreased to one half its original value) while the mass of the object is held constant.

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The Mars Curiosity rover was required to land on the surface of Mars with a velocity of 1 m/s. Given the mass of the landing veh

Aliun [14]

Answer:

The value is $A = 39315 \ m^2$

Explanation:

From the question we are told that

The velocity which the rover is suppose to land with is $v = 1 \ m/s$

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The drag coefficient is $C__{D}} = 0.5$

The atmospheric density of Earth is $\rho = 1.2 \ kg/m^3$

The acceleration due to gravity in Mars is $g_m = 3.689 \ m/s^2$

Generally the Mars atmosphere density is mathematically represented as

$\rho_m = 0.71 * \rho$

=> $\rho_m = 0.71 * 1.2$

=> $\rho_m = 0.852 \ kg/m^3$

Generally the drag force on the rover and the parachute is mathematically represented as

$F__{D}} = m * g_{m}$

=> $F__{D}} = 2270 * 3.689$

=> $F__{D}} = 8374 \ N$

Gnerally this drag force is mathematically represented as

$F__{D}} = C__{D}} * A * \frac{\rho_m * v^2 }{2}$

Here A is the frontal area

So

$A = \frac{2 * F__D }{ C__D} * \rho_m * v^2 }$

=> $A = \frac{2 * 8374 }{ 0.5 * 0.852 * 1 ^2 }$

=> $A = 39315 \ m^2$

8 0

3 years ago

When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq

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Answer:60 gm

Explanation:

Given

initial velocity of ball $u=0$

Force exerted by racquet $F=540 N$

time period of force $t=5\ ms$

final velocity of ball $v=45\ m/s$

Racquet imparts an impulse to the ball which is given by

$J=F\Delta t=\Delta P$

$J=540\times \Delta t=m(45-0)$

$m=\frac{540\times 5\times 10^{-3}}{45}$

$m=60\ gm$

8 0

3 years ago

A firecracker breaks up into three pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0

Mamont248 [21]

Answer:

$|P_3|=21.242m/s$

Explanation:

From the question we are told that:

Mass $m=200g=0.2$

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Speed $V_2=45.0m/s$

Generally the equation for Magnitude of the Third piece is mathematically given by

$P_1+P_2+P_3=0$

$|P_3|=|P_1+P_2|$

Where

$P_1=m_1v_1$

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And

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$|P_3|=21.242m/s$

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3 years ago

What is the instantaneous speed of the object after the five seconds?

OverLord2011 [107]

Answer:

12.5 m/s

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v-0=0.5*5*5

v=12.5 m/s

7 0

3 years ago