It is given that the bacteria in a colony doubles every 8 hours.
To find the population of bacteria 24 hours from now, we need to find the population of bacteria after every 8 hours.
The present population of the bacteria is 9315.
After 8 hours, the bacteria becomes double. So, the number of bacteria becomes 9315 x 2 = 18630.
Again after 8 hours, the bacteria becomes 18630 x 2 = 37260.
Again after 8 hours, the bacteria becomes 37260 x 2 = 74520.
Thus, after 24 hours from now, the population of the bacteria is 74520.
Y > x
y = 2(3+x)
y = 3x-2
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2(3+x) = 3x-2
2(3+x) - (3x-2) = 0
6 + 2x -3x + 2 = 0
8 -x = 0
x = 8
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y = 2(3+x) = 2(3+8) = 22
y = 3x-2 = 3*8 -2 = 22
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x = 8 ; y = 22
<u>Part 1</u>
The value of y is twice that of x, so the equation is y = 2x.
<u>Part 2</u>
Substituting in x = 14, we get y = 2(14) = 28.
We have that
<span>question 1
Add or subtract.
4m2 − 10m3 − 3m2 + 20m3
=(4m2-3m2)+(20m3-10m3)
=m2+10m3
the answer is the option
</span><span>B: m2 + 10m3
</span><span>Question 2:
Subtract. (9a3 + 6a2 − a) − (a3 + 6a − 3)
=(9a3-a3)+(6a2)+(-a-6a)+(-3)
=8a3+6a2-7a-3
the answer is the option
</span><span>B: 8a3 + 6a2 − 7a + 3
</span><span>Question 3:
A company distributes its product by train and by truck. The cost of distributing by train can be modeled as −0.06x2 + 35x − 135, and the cost of distributing by truck can be modeled as −0.03x2 + 29x − 165, where x is the number of tons of product distributed. Write a polynomial that represents the difference between the cost of distributing by train and the cost of distributing by truck.
we have that
[</span>the cost of distributing by train]-[the cost of distributing by truck]
=[−0.06x2 + 35x − 135]-[−0.03x2 + 29x − 165]
<span>=(-0.06x2+0.03x2)+(35x-29x)+(-135+165)
=-0.03x2+6x+30
the answer is the option
</span><span>C: −0.03x2 + 6x + 30
</span><span>
</span>
