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2 years ago

Find the length of DE.

Mathematics

1 answer:

Amanda [17]2 years ago

4 0

I think same as BC because it seem like its a reflected problem and x would be 23 and if 23-5 that would be 18 I think.

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Use the quadratic formula to solve x2 + 2x - 120 = 0. Think about what other method could also be used to solve this equation. a

pshichka [43]

Answer:

x = 10 , -12

Step-by-step explanation:

Solution:-

- The given quadratic equation is to be solved using the quadratic formula. The general form of a quadratic equation is:

$ax^2 + bx + c =0$

Where, [ a , b and c are constants ]

- The quadratic formula is given as:

$x = \frac{-b+/-\sqrt{b^2 - 4*a*c} }{2a}$

- The given equation is:

$x^2 + 2x - 120 = 0$

Where, a = 1 , b = 2 , c = -120

- Solve using quadratic formula:

$x = \frac{-2+/-\sqrt{2^2 - 4*1*(-120)} }{2*1}\\\\x = \frac{-2+/-\sqrt{4 + 480} }{2}\\\\x = \frac{-2+/-(22) }{2}\\\\\\x = 10 , -12$

7 0

3 years ago

In a class of 34 students, 19 of them are girls.

cluponka [151]

Answer:

55.8

Step-by-step explanation:

8 0

3 years ago

Tkanks, but how you can use the distributive Property to find the numbet of books abouts animals in the bookstore.

Sedbober [7]

If you would tell me the whole problem I could answer it

3 0

3 years ago

Preston's vegetable patch is 7 yards wide and 17 yards long. Preston wants to build a fence around the vegetable patch. The fenc

bezimeni [28]

Answer: 238$

Step-by-step explanation: 7 x 17 = 119 mutiply this x 2.00 = 238

6 0

2 years ago

Which expressions are completely factored? Select each correct answer. 30a6−24a2=3a2(10a4−8) 16a5−20a3=4a3(4a2−5) 12a3+8a=4(3a3+

irinina [24]

When factoring an expression, we need to identify the Greatest Common Factor of the expression (GCF). By definition, GCF is the product of prime factors involved with its Lowest Exponent.

We need to divide each term by the GCF to get the expression inside the parenthesis.

$30a^6-24a^2\\ GCF\; is \; 6a^2\\ \\ 30a^6-24a^2=6a^2(\frac{3a^6}{6a^2} -\frac{24a^2}{6a^2} )=6a^2(5a^4-4)\\ ---------------------\\ \\ 16a^5-20a^3\\ GCF \; is \; 4a^3\\ \\ 16a^5-20a^3=4a^3(\frac{16a^5}{4a^3} -\frac{20a^3}{4a^3})=4a^3(4a^2-5) \\ ---------------------\\ \\ 12a^3+8a\\ GCF \; is \; 4a\\ \\ 12a^3+8a=4a(\frac{12a^3}{4a}+\frac{8a}{4a})=4a(3a^2+2)\\ ---------------------\\ 24a^4+18\\GCF \; is \; 6\\\\24a^4+18=6(\frac{24a^4}{6} +\frac{18}{6})=6(4a^4+3) \\ ---------------------$

Conclusion:

From above we can conclude that the below expressions are factored completely

$16a^5-20a^3=4a^3(4a^2-5)\\ \\ 24a^4+18=6(4a^4+3)$

6 0

2 years ago

Read 2 more answers