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Margaret [11]
3 years ago
8

Find the length of DE.

Mathematics
1 answer:
Amanda [17]3 years ago
4 0
I think same as BC because it seem like its a reflected problem and x would be 23 and if 23-5 that would be 18 I think.
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ATRI has vertices T(-2,4), R(2,4), and 1(0,0). IS ATRI scalene, isosceles, or equilateral?
klasskru [66]
The answer is quilateral
3 0
3 years ago
What is another way to write 300+20+5?
Helga [31]
300+5+20 COULD BE ONE WAY
7 0
3 years ago
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3(x + 1) + 2 &lt; 11<br> Solve each inequality and graph the solution
maxonik [38]

Answer:

3x+3+2<11

Step-by-step explanation:

3x<11+3+2

3x<16

so now you divide 3 by the co-efficient

3x/3<16/3

so now 3 council 3 then you get x

x<16/3

x<5

now x is equal to 5

7 0
3 years ago
2. A particular resource class must perform at a level consistent with the rest of the school to avoid being discontinued. On th
Natali5045456 [20]

Answer:

t=\frac{71.86-78}{\frac{17.52}{\sqrt{14}}}=-1.311  

p_v =P(t_{13}  

If we compare the p value and a significance level assumed for example \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the actual true mean for the scores is NOT significant less than 78.  

Step-by-step explanation:

Data given and notation  

\bar X=71.86 represent the sample mean  

s=17.52 represent the standard deviation for the sample  

n=14 sample size  

\mu_o =78 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to determine if the mean is less than 78, the system of hypothesis would be:  

Null hypothesis:\mu \geq 78  

Alternative hypothesis:\mu < 78  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{71.86-78}{\frac{17.52}{\sqrt{14}}}=-1.311  

Calculate the P-value  

First we need to find the degrees of freedom given by:

df=n-1=14-1=13

Since is a one-side left tailed test the p value would be:  

p_v =P(t_{13}  

Conclusion  

If we compare the p value and a significance level assumed for example \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the actual true mean for the scores is NOT significant less than 78.  

3 0
3 years ago
Dan's dog-walking job pays $15 per hour. His job as a car-wash attendant pays $400 each week. Dan wants to know how many hours h
KengaRu [80]

Answer:

if his car-wash job gives him $400 then he should only work 8 hours walking dogs to reach 520. Though it says to earn 'more than $520' so maybe 9hrs?

Step-by-step explanation:

He already has $400, which leave $120. 120 divided by 15 equals 8.

5 0
3 years ago
Read 2 more answers
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