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3 years ago

Combine like terms.

1 answer:

5 0

Combine like terms 1-5
1)0.5x^4+10.5
2)5x+4
3)6a^2+16
4)4z^3+5z^2+z
5)p+4

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12percent of what number is 45

Molodets [167]

45 / 0.12 = 375
Answer: 375

8 0

3 years ago

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a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou

Fed [463]

Answer:

$\displaystyle P(A)=\frac{6}{11}$

Step-by-step explanation:

Probabilities

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

$\Omega=\{WW,WN,NW,NN\}$

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

$A=\{WN,NW\}$

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

$\displaystyle \frac{5}{11}$

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

$\displaystyle \frac{6}{10}$

Thus the option WN has the probability

$\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}$

Now for the second option NW. The initial probability to pick a non-white counter is

$\displaystyle \frac{6}{11}$

The probability to pick a white counter is

$\displaystyle \frac{5}{10}$

Thus the option NW has the probability

$\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}$

The total probability of event A is the sum of both

$\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}$

$\boxed{\displaystyle P(A)=\frac{6}{11}}$

7 0

2 years ago

How many distinguishable 11 letter "words" can be formed using the letters in MISSISSIPPI?

SCORPION-xisa [38]

This is given by the multinomial coefficient:

$\dbinom{11}{1,4,4,2}=\dfrac{11!}{1!4!4!2!}=34650$

If you're not familiar with the multinomial coefficient, you may be able to see it more clearly if you count the number of possible combinations taking each distinct letter $n$ times, where $n$ is the number of times it shows up in the original word.

$\underbrace{\dbinom{11}1}_{\text{M}}\underbrace{\dbinom{10}4}_{\text{I}}\underbrace{\dbinom64}_{\text{S}}\underbrace{\dbinom22}_{\text{P}}=\dfrac{11!}{1!10!}\dfrac{10!}{4!6!}\dfrac{6!}{4!2!}\dfrac{2!}{2!0!}=\dfrac{11!}{1!4!4!2!}$

4 0

3 years ago

If (angle)A and (angle)B are supplementary, and m(angle)A = 57°, what is m(angle)B?

Sedbober [7]

Answer:

123°

Step-by-step explanation:

Supplementary angles add up to be 180 degrees.

This means angles A and B will add up to be 180 degrees.

We can find the measure of angle B by subtracting 57 from 180

180 - 57

= 123

So, the measure of angle B is 123 degrees

7 0

2 years ago

THIS HOMEWORK IS SO HARD WALLAHI CAN SOMEONE HELP PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS

Lubov Fominskaja [6]

Answer:

may be 5 I'm not a 100%sure

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3 years ago

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