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max2010maxim [7]
3 years ago
5

Solve questions 1-3.Show your work.

Mathematics
2 answers:
AnnyKZ [126]3 years ago
7 0
We need more info
Step explain to
svet-max [94.6K]3 years ago
6 0
I cant see that bs whattttttt
You might be interested in
3.27x+1.28y+1.83x−2.77y
Firdavs [7]

Answer:

5.1x - 1.49y

Step-by-step explanation:

We need to add or substract like terms.

like terms are the terms that have the same variable, in this case:

3.27x and 1.83x are like terms, and adding them we get:

3.27x + 1.83x = 5.1x (you add only the coefficients and the x stays the same)

we do the same for the terms with 'y':

1.28y and −2.77y are like terms, but in this case we must substract because of the − sign:

1.28y −2.77y = -1.49y

the final answer is the conjunction of the two results that we obtained:

5.1x - 1.49y

8 0
3 years ago
If sin(x) = 0 and cos(x) = 1, what is cot(x)?
Nata [24]

Answer:

undefined

Step-by-step explanation:

Sin(x) = 0 where x = 0

Cos(x) = 1 where x = 0

Cot(0) is undefined

3 0
3 years ago
Read 2 more answers
A square piece of paper has an area of 36 square inches what is the perimeter of the paper​
Gekata [30.6K]

Lets represent the side of the square as s , since we know the area is 36. write s

{s}^{2}  = 36

s = \sqrt{36}

the square root of 36 is 6. So, we know the side is 6. The formula for perimeter is P= s+s+s+s , but since it is a square and all the sides are equal, for a perimeter of a square you can do p= 4s , now substitute 6 for s to get 4(6)=24 so the perimeter of a square would be 24 inches

6 0
3 years ago
1) Subtract 2x + 4 from 3x - 2<br> ?
Dmitry_Shevchenko [17]

Answer:

x + 2 is the answer I think...

4 0
3 years ago
Read 2 more answers
For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?
irakobra [83]

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is \frac{2x^2+8x}{(x+4)(x^2-9)}

To find for what value of x is undefined in the given expression :

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}

=\frac{2x}{x^2-9}

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}

If we put x=3 in the above expression we get

\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}

=\frac{6}{9-9}

=\frac{6}{0}

Therefore \frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}

The value at x =3 is undefined for the given expression

7 0
3 years ago
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