If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Please say brainliest.
It would be 18 degrees.
5% of 360(the total number of degrees in a circle) = 18 degrees
15.6 kilometers rounded down because it is not safe to go above what has been approved
Y = -2(x-5)^2 + 4
Note: vertex form is 0, f(x), y, or nothing= a(x-h)^2 + k
The opposite of the x value of the vertex is h
The y value value of the vertex is k.
Find a. Plug in (6,-10)
-10 = a(6-5)^2 + 4
-10 = 1a + 4
-10 = 5a
a = -2