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blagie [28]
3 years ago
5

1) ¿Cuáles son los sentidos comunes que se pueden utilizar, para identificar un metal, gases o líquido?

Chemistry
1 answer:
kifflom [539]3 years ago
5 0

The question is another language. Translation in English language is as following:

What are the common sensors that can be used to identify metal, gas or liquid?

Answer:

<u>Common sensors that can be used to identify metal, gas or liquid are as following:</u>

  • Inductive Proximity Sensor: Inductive proximity sensors are able to detect metals only. It generates output signal or electrical signal when any metal object come nearby its sensing area.
  • Handheld flammable gas detectors: they are commonly used to detect gas leakage such as natural gas lines, butane tanks, or any other combustible gas.
  • Optical level sensors: this sensor is used to detect liquids including the interface between two immiscible liquids and the occurrence of sediments.

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The electron configuration of an element is 1s22s22p¹. How many valence electrons does the element have
Cloud [144]

Answer:

\huge\boxed{\sf 3 \ electrons}

Explanation:

<h3>Electronic configuration:</h3>

1s^22s^22p^1

The outermost/valence shell is the second one, seeing from the electronic configuration.

<h3>Valence electrons:</h3>

= 2 + 1 = 3 (electrons are raised to the power in the electronic configuration)

Since, the valence shell here is 2, the electrons of second shell will be counted as valence electrons.

\rule[225]{225}{2}

4 0
2 years ago
What is the energy of an electromagnetic wave with a electromagnetic wave with a frequency of 3 * 10 Hz ?
Olin [163]

Answer:

E=1.989*10^{-32}J

Explanation:

From the question we are told that:

Frequency f=3 * 10 Hz

Generally the equation for Energy of an electromagnetic wave is mathematically given by

 E=hf

Where

  h=Planck's constant

  h=6.62607015 * 10^{-34}

Therefore

 E=6.62607015 * 10^{-34}*3 * 10

 E=1.989*10^{-32}J

8 0
3 years ago
1.6x10^23 lead atoms. Find the weight in grams
Ber [7]
Moles of lead(Pb) = 1.6x10^23/6.02x10^23 = 0.265 moles.

Weight of lead = moles x atomic weight of lead
                         =  0.265x207.2
                         =  54.908 grams.

Hope this helps!
5 0
3 years ago
(i)What happens when an aqueous solution of sodium sulphate reacts with an aqueous
MAXImum [283]

Explanation:

2nacl+baso4

the orginal equation is

Na2so4+Bacl2

then na react with cl and ba react with so4

4 0
3 years ago
Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C.
evablogger [386]

Answer:

The total amount of heat needed = 72.2116  kJ

Explanation:

Given that ;

the mass of acetic acid = 120.0 g

The initial temperature T_1 = 16.7 °C  = (16.7 + 273.15 ) K = 298.85 K

The standard molar mass of acetic acid = 60.052  g/mol

Thus ; we can determine the number of moles of acetic acid;

number of moles of acetic acid = mass of acetic acid/ molar mass of acetic acid

number of moles of acetic acid = 120.0 g/ 60.052 g/mol

number of moles of acetic acid =  1.998 moles

For acetic acid:

The standard boiling point  T_2 = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K

The enthalpy of vaporization of acetic acid \Delta H_{vap} = 23.7 kJ/mol

The heat capacity of acetic acid   c = 2.043  J/g.K

The change in temperature Δ T = T_2 - T_1

Δ T = (391.25 - 289.85)K

Δ T = 101.4 K

The amount of heat needed to bring the liquid acetic acid at 16.7°C to its boiling point is ;

q = mcΔT

From our values above;

q = 120 g ×  2.043  J/g.K × 101.4 K

q = 24859.2  J

q = 24859 /1000 kJ

q = 24.859 kJ

we have earlier calculated our number of moles o f acetic acid to be 1.998 moles;

Thus;

The needed amount of heat = \Delta_{vap} *numbers \ of  \ moles

The needed amount of heat = 23.7 \ kJ/mol * 1.998 \ moles

The needed amount of heat = 47.3526 kJ

Hence;

The total amount of heat needed = 24.859 kJ + 47.3526 kJ

The total amount of heat needed = 72.2116  kJ

4 0
3 years ago
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