The volume of NH₃ produced at STP : 0.237 L
<h3>Further explanation</h3>
Reaction
N₂ + 3H₂ → 2NH₃
1 mol = 6.02 x 10²³ particles
9.6 X 10²¹ molecules of Hydrogen, mol :
mol H₂ : mol NH₃ = 3 : 2
mol NH₃ :
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). <em>At STP, Vm is 22.4 liters/mol.</em>
The volume of NH₃ :
<em />
Answer:
47.5 g of water can be formed
Explanation:
This is the reaction:
CH₄ + 2O₂ → CO₂ + 2H₂O
Methane combustion.
In this process 1 mol of methane react with 2 moles of oxygen to produce 2 moles of water and 1 mol of carbon dioxide.
As ratio is 1:2, I will produce the double of moles of water, with the moles of methane I have.
1.320 mol .2 = 2.64 moles
Now, we can convert the moles to mass (mol . molar mass)
2.64 mol . 18g/mol = 47.5 g
<span>Weathering, erosion, and deposition.</span>
The solubility of gases is not constant in all conditions. If temperatures differ, the solubility of gases differ. Additionally, the solvent (the substance that is mixed with a gas to form a solution) can affect the solubility of a gas (its ability to become dissolved and in turn contribute to a formed amount of concentration).
The solubility of a gas is dependent on temperature. An increase in temperature results in a decrease in gas solubility in water, while a decrease in temperature results in an increase of gas solubility in water. To comprehend this phenomena one must consider the two processes that occur when a non-polar gas is added to water. Initially a type of cavity develops when adding the solute to the solvent, representative of the conformation and overall size of the added gas, and in turn a successive process occurs in which attractive forces between the gas and water molecules are stimulated. It is this dual process that induces the water to produce both attractive and repulsive forces. By examining the water on a microscopic level and the components of the water that portray propinquity to the non-polar gases, temperature dependencies become observable.