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Gnesinka [82]
3 years ago
5

A heart beats 10 times in 10 seconds. How many times does it beat in 1 minute?

Physics
2 answers:
DanielleElmas [232]3 years ago
8 0
The heart will beat 60 times in 1 minute.
djyliett [7]3 years ago
3 0

Answer:

60

Explanation:

60secs = 1 minute

if you want to show you work further then

10 divided by 10 = 1

so each second is 1 heart beat

so then just 60 divided by 10 equals 6

so then just do 6 times 10 equals 60 beats

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A ball of mass m is thrown straight upward from ground level at speed v0. At the same instant, at a distance D above the ground,
Alla [95]

Answer:

Explanation:

Let the balls collide after time t .

distance covered by falling ball

s₁ = v₀ t + 1/2 g t²

distance covered by rising ball

s₂ = v₀ t - 1/2 g t²

Given ,

s₁ + s₂ = D

D = v₀ t + 1/2 g t² + v₀ t - 1/2 g t²

= 2v₀ t

t = D / 2v₀

s₂ = v₀ t - 1/2 g t²

= v₀ x D / 2v₀ - (1/2) x  g x D² / 4v₀²

= D / 2 - gD² / 8 v₀²

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3 years ago
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C. element only one substance
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3 years ago
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A nasa spacecraft measures the rate r of at which atmospheric pressure on mars decreases with altitude. the result at a certain
Lesechka [4]

Answer:4.21 \times 10^{-10} J/cm^4

1 kPa= 10^3 Pa

1 km=10^5 cm

1kPa/km=0.01 Pa/cm

1kPa/km=10^{-8} J/cm^4

\Rightarrow r= 0.0421 kPa/km= 0.0421 kPa/km \times \frac{10^{-8} J/cm^4}{1 kPa/km}= 0.0421 \times 10^{-8}J/cm^4=4.21 \times 10^{-10} J/cm^4

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3 years ago
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If a car is traveling at a velocity of +10m/s suddenly turns around and continues at the same speed, what is its new velocity?
Lady_Fox [76]

Answer:

-10m/s

Explanation:

only the magnitude of the velocity will change due to the change in direction of the car.

6 0
4 years ago
A 2 kg blue car is moving 6 m/s to the right and collides with a 3 kg red car that is moving 2 m/s to the left. The cars collide
snow_lady [41]

Answer:

Their velocity after the collision is 1.2 m/s, to the right.

Explanation:

Given;

mass of the blue car, m₁ = 2 kg

initial velocity of the blue car, u₁ = 6 m/s

mass of the red car, m₂ = 3 kg

initial velocity of the red car, u₂ = 2 m/s

let the blue car moving to the right be in positive direction

also, let the red car moving to the left be in negative direction

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ - m₂u₂ = v(m₁ + m₂)

where;

v is their velocity after the collision

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v = 6/5

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Therefore, their velocity after the collision is 1.2 m/s, to the right.

7 0
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