Answer:
check the point where the output device's field wiring is connected to the output rack. ( C )
Explanation:
Given that an indicator light on the output module is indicating that a signal has been sent to the output point where the failed single output device is connected , the best line of action to properly indicate the output device that has filed in the PLC system, is to check the point where the output device's field wiring is connected to the output rack in the PLC system.
A PLC system is a computer control system ( especially Industrial ) that helps in the monitoring the states of input and output devices in an industry.
Answer:
9 ft*lb
Explanation:
super simple but you just have to understand that the integral is going with the curve
work = integral a to b of f(x)dx = integral 0 to 9 of 10/(1+x)^2dx = 9ft*lb
Answer:
The velocity is 
Explanation:
Given:
Force = 500N
Distance s= 0
To find :
Its velocity at s = 0.5 m
Solution:






Using the relation,



Now integrating on both sides


![\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bv%5E%7B2%7D%7D%7B2%7D%5Cright%5D_%7B0%7D%5E%7B2%7D%3D%5Cleft%5B%5Cleft%2830.77%20s-19.23%20s%5E%7B2%7D%5Cright%29%5Cright%5D_%7B0%7D%5E%7B0.5%7D)
![\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bv%5E%7B2%7D%7D%7B2%7D%5Cright%5D%3D%5Cleft%5B%5Cleft%2830.77%280.5%29-19.23%280.5%29%5E%7B2%7D%5Cright%29%5Cright%5D)
![\left[\frac{v^{2}}{2}\right]=[15.385-4.807]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bv%5E%7B2%7D%7D%7B2%7D%5Cright%5D%3D%5B15.385-4.807%5D)
![\left[\frac{v^{2}}{2}\right]=10.578](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bv%5E%7B2%7D%7D%7B2%7D%5Cright%5D%3D10.578)




This is an example of slowing down because you encountered heavy traffic or just got tired.
Also, the numbers show acceleration.
Power = (voltage) x (current)
500 W = (120 v) x (current)
Current = (500 w) / (120 v) = 4-1/6 amperes .
Power and current are both rates.
Power is the rate of using energy ... joules per second.
Current is the rate of flowing charge ... coulombs per second.
Neither quantity depends on how long you keep it up.
They're both going on continuously while the vacuum is running.