Question

A mouse jumps horizontally from a box of height 0.25m.  If the mouse jumps with a speed of 2.1 m/s, how far from the box does the mouse land?

Answer 1

Time to fall 0.25 meter vertically from rest:

D = (1/2) (g) (t²)

0.25m = (1/2) (9.8 m/s²)(t²)

t² = (0.25m) / (4.9 m/s²)

t² = 0.051 sec²

t = 0.226 second

In that amount of time, the mouse sails out

(2.1 m/s) (0.226 sec) = 0.474 meter

horizontally.

Answer 2

The mouse would land 0.47 m away from the box.