A mouse jumps horizontally from a box of height 0.25m. If the mouse jumps with a speed of 2.1 m/s, how far from the box does th
e mouse land?
2 answers:
Time to fall 0.25 meter vertically from rest:
D = (1/2) (g) (t²)
0.25m = (1/2) (9.8 m/s²)(t²)
t² = (0.25m) / (4.9 m/s²)
t² = 0.051 sec²
t = 0.226 second
In that amount of time, the mouse sails out
(2.1 m/s) (0.226 sec) = <em>0.474 meter</em>
horizontally.
The mouse would land 0.47 m away from the box.
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