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viktelen [127]
3 years ago
10

A mouse jumps horizontally from a box of height 0.25m.  If the mouse jumps with a speed of 2.1 m/s, how far from the box does th

e mouse land?
Physics
2 answers:
Nookie1986 [14]3 years ago
7 0

Time to fall 0.25 meter vertically from rest:

D = (1/2) (g) (t²)

0.25m = (1/2) (9.8 m/s²)(t²)

t² = (0.25m) / (4.9 m/s²)

t² = 0.051 sec²

t = 0.226 second

In that amount of time, the mouse sails out

(2.1 m/s) (0.226 sec) = <em>0.474 meter</em>

horizontally.


Sladkaya [172]3 years ago
3 0

The mouse would land 0.47 m away from the box.

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3 years ago
Your starship, the Aimless Wanderer,lands on the mysterious planet Mongo. As chief scientist-engineer,you make the following mea
melisa1 [442]

Answer:

m = 1.26*10²⁵ kg.

Explanation:

Assuming that the mass of the stone is much smaller than the mass of the planet, we can get the mass, applying the Universal Law of  Gravitation to both masses, as follows:

Fg = G* ms* mp / rp²

Now, if we apply Newton's 2nd Law to the mass of the stone, we can get the gravitational acceleration, as follows:

Fg = ms*a = ms*g ⇒ g = G*mp / rp²

First of all, we need to get the value of g.

Assuming that this acceleration is constant, we can appy the kinematic equations to this situation.

We know that the stone is thrown upward with an initial velocity vo = 15 m/s.

At the highest point in the trajectory, just before of changing direction, the stone comes momentarily to a stop.

At this point, applying the definition of acceleration, we can write:

vf = vo -g*t ⇒ 0 = vo -gt ⇒ g = vo/t (1)

We have the total time since the stone was thrown upwards, not the one used for the upward trajectory.

It can be showed, using the expression for the displacement (which is the same in both directions) that the time used for going up, it's the same used to go down, so the time that we need to put in (1). is just the half of the total time.

So, replacing in (1) we get the value of g, as follows:

g = 15 m/s / 4.5 s = 3.33 m/s²

Now, we can replace this value in the equation that gives us g based in the Universal Law of Gravitation, as follows:

g=G*mp / rp² (2)

Before solving for mp, however, we need to get the value of the radius of the planet.

Assuming that it's a perfect sphere, we can get this value from the value of the circumference at the planet's equator:

rp = 2*π*rp / 2*π ⇒ rp = 1.0*10⁵ km / 2*π = 15,915 km.

With this value for  rp, we can solve (2) for mp, as follows:

mp= g*rp² / G = 3.33 m/s² * (15,915 km)² / 6,67*10⁻¹¹ N.m²/kg²

mp = 1.26*10²⁵ kg.

8 0
2 years ago
3
Assoli18 [71]
Answer: 40.4M/s

Solution: 46.6/1.15 = 40.4347826 then round it to a single decimal point, since 3 is lower than 5 it will be rounded to 40.4
8 0
2 years ago
Define a rotation of the earth answer fast
stiv31 [10]

Answer:

here u go

Explanation:

Earth's rotation is the rotation of planet Earth around its own axis. Earth rotates eastward, in prograde motion. As viewed from the north pole star Polaris, Earth turns counterclockwise.

8 0
3 years ago
A train traveling at 10 m/s accelerated at a rate of
ella [17]
<h3>Answer:  28 m/s</h3>

Work Shown:

  • Vi = starting or initial velocity = 10 m/s
  • Vf = unknown final velocity
  • a = acceleration = 3 m/s^2
  • t = duration of time = 6 seconds

Use those values in the following kinematic equation

Vf = Vi + a*t

Vf = 10 + 3*6

Vf = 10 + 18

Vf = 28

The final velocity is 28 m/s

8 0
2 years ago
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