Answer:
143 kW
Explanation:
Given that
Diameter of the beam, d = 1 mm
Wavelength of the beam, λ = 193 nm
Time used by the pulse, t = 14 ns
Energy of the pulse, U = 2 mJ
Recall that Power can be mathematically calculated using the relation,
Power = Work Done / Time,
To solve this, we apply the formula
P = U / Δt
P = 2*10^-3 J / 14*10^-9 s
P = 142857 W
P = 143 kW
I think your answer is volume
I can't see that cube from here.
But if the length of the side of the cube is ' K ' units,
then the surface area of the cube is 6K² units², and
the volume of the cube is K³ units³.
The ratio of the surface area to the volume is
(6K² units²) / (K³ units³) = (6) / (K units) .
So for example, if the side of the cube is 2 inches, then
the ratio of surface area to volume is "3 per inch".
That's the answer. I did the whole thing in order to earn
the points, but I don't expect you to understand much of it,
because I see from your username that you suck at math.
I'm sorry you decided that. Now that you've put up the
brick wall, it'll be even harder for any math to find its way
in there, and you'll miss out on a lot of the fun.
V^2=u^2 +2aS
U is found first by considering that first 8 secs and using v=u+at. {different v and u though}
V=-u+gt.
Magnitude of u = magnitude of v if there is no resistance ( because the conservation of energy says the k. E. must be the same when it passes you as when it left your hand).... up is negative here, down is positive.
V+v=gt
2v= g x 8
V=4xg.= the initial velocity for the next calculation
V^2=(4g)^2+(2xgx21)
So v can be calculated.
