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zimovet [89]
4 years ago
14

What is the purpose of a valve?

Physics
2 answers:
user100 [1]4 years ago
8 0
To prevent blood backflow!

Aleks04 [339]4 years ago
5 0
In general or valves are used to turn off or proportionately control the flow of fluid through any system. Your faucet in your bathroom is a type of valve. You can turn it all the way off and all the way on, but you can also turn it on a little bit at a time.
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How can a soccer ball and a small tennis ball bouncing relates to newtons first law interita?
Anna35 [415]

Answer:

I think it has something to do with both inertia and gravity?

7 0
3 years ago
A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the wate
lilavasa [31]

Take the stone's position at ground level to be the origin, and the downward direction to be negative. Then its position in the air y at time t is given by

y=100\,\mathrm m-\dfrac g2t^2

Let d be the depth of the well. The stone hits the bottom of the well after 5.00 s, so that

-d=100\,\mathrm m-\dfrac g2(5.00\,\mathrm s)^2\implies d=\boxed{22.6\,\mathrm m}

7 0
3 years ago
The real advantage to hydrostatic weighing is that it __________.
katovenus [111]

The real advantage to hydrostatic weighing is that it gives one of the most accurate measurements of body fat.

7 0
3 years ago
Read 2 more answers
What kind of quantity is displacement?
Serhud [2]

Answer:

calar quantity, length of path. displacement: vector quanity, "as the crow flies" difference between start and finish regardless of path taken. Term.

Explanation:

8 0
3 years ago
If a farsighted person has a near point that is 0.600 mm from the eye, what is the focal length f2f2f_2 of the contact lenses th
Readme [11.4K]

Answer:

0.22mm

Explanation:

A far sighted person is a person suffering from long sightedness i.e such individual can only see far distant object clearly but not near distant object. The defect is corrected using convex lens.

Since convex lens is used, the focal (f) length of the lens is positive and the image distance (v) is also positive.

Using the lens formula,

1/f = 1/u + 1/v

Where u is the object distance = 0.35mm

v = 0.6mm

1/f = 1/0.35+1/0.6

1/f = 2.86 + 1.67

1/f = 4.53

f = 1/4.53

f = 0.22mm

The focal length of the contact lenses will be 0.22mm

5 0
3 years ago
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