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vredina [299]
3 years ago
8

Identify the point (x1, y1) from the equation: y – 9 = 3(x + 2) (–2, 9) (9, –2) (2, –9) (–8, 2)

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0
Its -8,2 text me if you want to know why
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AB and DE are chords that intersect at point F inside circle C as shown. If the measure of arc EA= 50 degrees and the measure of
defon

Answer:

Part 1) m\angle AFE=55^o

Part 2) m\angle EFB=125^o

Step-by-step explanation:

Part 1) what is the measure of angle AFE

we know that

The measure of the interior angle is the semisum of the arches that comprise it and its opposite.

<u>Note:</u> In this problem the correct measure of arc EA is 40 degrees (see the picture)

so

m\angle AFE=\frac{1}{2}(arc\ EA+arc\ DB)

substitute the given values

m\angle AFE=\frac{1}{2}(40^o+70^o)=55^o

Part 2) what is the measure of angle  EFB?

we know that

m\angle AFE+m\angle EFB=180^o ---> by supplementary angles (form a linear pair)

so

substitute the given value

55^o+m\angle EFB=180^o

m\angle EFB=180^o-55^o=125^o

8 0
4 years ago
What is the next number 9 16 24
Gemiola [76]
Its gonna be 9,16,24,33
8 0
4 years ago
Read 2 more answers
Which rational number equals 0 point 3 with bar over 3? Question 2 options: 1) 1 over 5 2) 1 over 3 3) 3 over 10 4) 3 over 5
Vedmedyk [2.9K]

9514 1404 393

Answer:

 2) 1/3

Step-by-step explanation:

The repeating decimal can be converted to a fraction by multiplying it by 10^n and subtracting the original value. n = number of repeating digits. This process cancels all of the repeating digits, so you can find the equivalent fraction.

  x=0.\overline{3}\\\\10x -x=3.\overline{3}-0.\overline{3}=3\\\\x=\dfrac{3}{9}\\\\0.\overline{3}=\dfrac{1}{3}

_____

Your calculator can help you answer this:

  1/5 = 0.2

  1/3 = 0.333.... (repeating) . . . . the number you're looking for

  3/10 = 0.3

  3/5 = 0.6

7 0
3 years ago
You picked two marbles from a bag and record their color. How can you make your selections independent events? Dependent events?
olga55 [171]

Answer:

Let's suppose the next case:

We have a bag, where there are 5 red marbles, and 5 blue marbles.

We have a total of 10 marbles.

Suppose that we pick a marble and we do not replace it, and suppose that the first one is a red marble.

Then now we have in the bag a total of 4 red marbles and 5 blue marbles.

Now let's find the probability of picking a blue marble, this will be equal to the quotient between the number of blue marbles (5) and the total number of marbles (9)

P = 5/9

Now, suppose that instead of a red marble in the first pick, we had a blue marble.

Then now we have 4 blue marbles and 5 red marbles in the bag.

Again, the probability of picking a blue marble will be equal to the quotient between the number of blue marbles (4) and total numbergof marbles (9)

P = 4/9

Then the first pick does affect the probabilities for the second pick, this means that if we do not replace the first marble we pick, then the events will be dependent.

Now, if we replaced the first marble we picked (we put it again in the bag) then the number of blue marbles and red marbles is always the same, then in this case bot events will be independent (the first event will not affect the second event)

4 0
3 years ago
B. Determine the values of a and b so that f is continuous.<br><br> Please help!
wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to  4a-2b+3 = 4\\\\  \therefore \ \ 4a-2b = 1\\\\

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\  

So,

\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3

\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\

In equation a multiply the by -2 and then add in the equation b:

\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to   a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to   -2b = -1\\\\ \to b = \frac{1}{2}  

So, the value of a \ and \ b= \frac{1}{2}

4 0
3 years ago
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