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dsp73
4 years ago
7

Write a number with 4 hundred 9 tens 3 ones

Mathematics
1 answer:
shtirl [24]4 years ago
3 0
493 ?????????????????????
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Nine times the input minus seven is equal to the output. If the input is -1, what is the output?
lara [203]

Answer:

-16

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can somebody help me please .
sineoko [7]

Answer:

The graph of the equation is given below.

Step-by-step explanation:

We are given the equation, -3x-4y=4

On simplifying, we get,

-3x-4y=4 i.e. 4y=-3x-4

So, the table is given by,

x                       4y=-3x-4                                       y

-4                     4y=-3\times (-4)-4 i.e. 4y=8             2

0                      4y=-3\times (0)-4 i.e. 4y=-4            -1

4                      4y=-3\times 4-4 i.e. 4y=-16             -4

Thus, the graph of the equation is given below.

5 0
3 years ago
Find the sum of the series.<br><br> Series from 0 to infinity <br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B7%5En%7D%7Bn%213%
Mashcka [7]

Recall that

e^x=\displaystyle\sum_{n=0}^\infty\frac{x^n}{n!}

Plug in x=\frac73 and you get your series, so the given series has a value of e^{7/3}.

8 0
3 years ago
The value -1 is a solution for x^2 - 6x + 5 = 0 True or False?
solmaris [256]
False -1 is not a solution.
3 0
3 years ago
Y^3-9y^2+y-9 I don't know how to solve this can you help
aleksley [76]
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?

In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0    and    (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.

So you're final answer should be y = i and 9
3 0
4 years ago
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