Answer:
Explanation:
V = 100sin(ωt) + 150cos(ωt)
let x = ωt
V = 100sin(x) + 150cos(x)
a maximum or minimum will occur when the derivative is zero
V' = 100cos(x) - 150sin(x)
0 = 100cos(x) - 150sin(x)
100cos(x) = 150sin(x)
100/150 = sin(x)/cos(x)
0.6667 = tan(x)
x = 0.588 rad
V = 100sin(0.588) + 150cos(0.588)
V = 180.27756
as the maximum will not occur until ωt = 0.588 radians, for a cosine function we subtract that amount as a phase angle φ
V = 180.3 cos(ωt - 0.588)
or as a sine function, the phase angle lags the cosine by a difference of π/2
V = 180.3sin(ωt - (0.588 - π/2)
V = 180.3sin(ωt + 0.983)
Can I still get 5 points bc u already figured it out
Answer:
Explanation:
The final angle speed of the merry-go-round is determined with the help of the Principle of Angular Momentum Conservation:
![(270\,kg\cdot m^{2})\cdot \left(8\,rpm\right) = [270\,kg\cdot m^{2}+(27\,kg)\cdot (1.80\,m)^{2}]\cdot \dot n](https://tex.z-dn.net/?f=%28270%5C%2Ckg%5Ccdot%20m%5E%7B2%7D%29%5Ccdot%20%5Cleft%288%5C%2Crpm%5Cright%29%20%3D%20%5B270%5C%2Ckg%5Ccdot%20m%5E%7B2%7D%2B%2827%5C%2Ckg%29%5Ccdot%20%281.80%5C%2Cm%29%5E%7B2%7D%5D%5Ccdot%20%5Cdot%20n)
Answer:
The force will be attractive.
Explanation:
Since we the sum of the charges is 0 they must have opposite charges and equal magnitudes.
And Opposite charges are attaractive towards each other.
The first one is: head
Second one is: 10 trillion km
