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3 years ago

19)

2 answers:

6 0

Momentum (M) is the product of the mass (m) of an object and its velocity (v). This may be mathematically expressed through the following equation.
M = m x v
If the large truck has more momentum than the small car, it either has a greater speed or greater speed than the car. The answer to the question above would be letter A.

Kobotan [32]3 years ago

5 0

Answer:

A. A large truck has much larger mass.

Explanation:

Momentum is the product of mass and velocity of a body.

P = m x v

A body which has much larger mass than a body having smaller mass travelling at same velocity would have greater momentum.

In the given question, a large truck and a small car are driving down a highway. Even with small velocity, a large truck would have greater momentum because of its large mass than the small car.

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A satellite has a mass of 5850 kg and is in a circular orbit 4.1 x10 to the 5th power m above the surface of a planet. The perio

koban [17]

Answer:

W = 24.28 kN

Explanation:

given,

Mass of satellite = 5850 Kg

height , h = 4.1 x 10⁵ m

Radius of planet = 4.15 x 10⁶ m

Time period = 2 h

= 2 x 3600 = 7200 s

Time period of satellite

$T = \dfrac{2\pi}{R}\sqrt{\dfrac{(R+h)^3}{g}}$

R is the radius of planet

h is the height of satellite

$T^2 = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{g}}$

now calculation of acceleration due to gravity

$g = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{T^2}}$

$g = \dfrac{4\pi^2}{(4.15\times 10^6)^2}\ {\dfrac{(4.15\times 10^6+4.1\times 10^5)^3}{(7200)^2}}$

g = 4.15 m/s²

True weight of satellite

W = m g

W = 5850 x 4.15

W = 24277.5 N

W = 24.28 kN

True weight of the satellite is W = 24.28 kN

8 0

3 years ago

A student places his hand in front of a plane mirror as shown in

NARA [144]

Answer:

Explanation:

Plane mirrors always form virtual images meaning although the object appears to be in the other side of the mirror the light rays actually originate in front of it. The image is inverted meaning that when you lift your right hand it shows your left hand rising. and with true orientation.

7 0

4 years ago

If an athlete leaps vertically at 4.0m/s, what maximum height does he reach?

joja [24]

Hello
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration: $g=-9.81~m/s^2$ , and where the negative sign means it points downwards, against the direction of the motion.

Therefore, we can use the following formula to solve the problem:
$v_f^2 = v_i^2 + 2gS$
where $v_i=4~m/s$ is the initial vertical velocity of the athlete, $v_f=0$ is the vertical velocity of the athlete at the maximum height (and $v_f=0~m/s$ at maximum height of an accelerated motion) and S is the distance covered between the initial and final moment (i.e., it is the maximum height). Re-arranging the equation, we get
$S= \frac{v_f^2-v_i^2}{2g}=0.82~m$

3 0

3 years ago

5. How does privatization contribute to productivity?

tangare [24]

Answer:

increased competition

Explanation:

3 0

2 years ago

Un vehicle surt, en un instant, d'un punt A cap a un altre punt B amb una velocitat constant de 36 km/h. Després d'un minut(60 s

kati45 [8]

Ask Siri or goggle has all answers

6 0

3 years ago